Need help with my hw.

Write a program. Commence the change to be dispensed from a vending machine. An item machine can cost between $0.25 send a dolla

SSSSS [86.1K]

Answer:

Explanation:

The objective of this question is to write a java program for a vending machine.

/* This program finds out what amount the vending machine is going to dispense. A given item in the machine can cost between $0.25 and a dollar in five-cent increments (25, 30, 35, 40...90, 95 or 100), and the machine accepts only a dollar bill to pay for the item. */

// Compile: javac PP10. java

// Run: java PP10

// imported the scanner class from util package.

import java. util. Scanner;

//class declaration

public class PP10 {

// main method is defined here.

public static void main(String[] args)

{

// declaration of the variables.

Scanner keyboard=new Scanner (System.in):

//taking the string type input

int nl, amount, n2, n3, n4, n5;

System.out.println("Enter price of item (from 20

cents to a dollar, in 5-cents) :");

n1=keyboard. nextInt ();

System.out.println("You bought an item for "+n1+"

cents and gave me a dollar");

System.out.println ("so your change is ");

//the amount is first calculated.

amount=100-n1;

// quarter value is calculated

n2=amount/25;

// rest amount is get here.

amount=amount%25;

// dime value is calculated

n3-amount/10;

// rest amount is calculated

amount=amount%10;

// value of nickel is calculated here

n4=amount/5;

// rest amount is calculated

amount=amount%5;

//at last the number of pennies is get

n5=amount;

// Display output

System. out . println(n2+" quarters") :

System. out . println(n3+" dimes") ;

System. out . println(n4+" nickels") ;

System. out . println(n5+" pennies") ;

}

Output:

Enter the price of the item (from 20 cents to a dollar, in 5 - cents):

So, you bought an item for $0.45 and gave me one dollar; thus, your change is

2 quarters

0 dimes

1 nickel

0 pennies

4 0

3 years ago

6. Write a C++ program to print the largest three elements in an array.

jasenka [17]

Answer:

if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.

7 0

2 years ago

What component of a change management program includes final testing that the software functions properly

ValentinkaMS [17]

A component of a change management program which includes final testing that the software functions properly is: C) Release management.

SDLC is an acronym for software development life cycle and it can be defined as a strategic methodology that defines the key steps, phases, or stages for the design, development and implementation of high quality software programs (applications).

In Computer science, there are seven (7) phases involved in the development of a software program and these include the following;

Planning

Analysis

Design

Development (coding)

Testing

Deployment

Maintenance

At the final testing stage, a component of a change management program which ensure that the software functions properly is known as release management.

Read more on software here: brainly.com/question/26324021

#SPJ1

Complete Question:

What component of a change management program includes final testing that the software functions properly?

A) Request management

B) Change management

C) Release management

D) Iteration management

5 0

1 year ago

What are the first and the last physical memory addressesaccessible using

Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

NOTE-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10000 +00000 = 10000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10000 +0FFFF =1FFFF (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0FFF0 +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0FFF0 +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

00010 +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

00010 +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

E0000 +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

E0000 +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10020 +00000=10020 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10020 +0FFFF =2001F (from note)

6 0

3 years ago

What is the output of the following?

lys-0071 [83]

Answer: a. the number is: 14

Explanation:

i mean just try to write in 7 instead of x in the second line

then it would say the number is: ....

what is 7 times 2?

14

so the answer is a

5 0

2 years ago

Need help with my hw.​

Need help with my hw.