If Anne gave birth to four males and four females, and they all gave birth the same way again, they would have eight males, but if it were to happen again, there would be 12 males and 12 females in total if you don't count all of the females giving birth EACH to four males and four females. Otherwise it would be 40 males, and 40 females.
Seems like you already have the answer so peace
Answer:
b
Step-by-step explanation:
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
