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Lena [83]
3 years ago
13

Need some help with model contexts with two variable expressions

Mathematics
1 answer:
malfutka [58]3 years ago
5 0
Answer is
=1720 pounds
30s, 70 L

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Quiz
Tasya [4]

Answer:

1603

Step-by-step explanation:

3^3*4^3-5^3

__________

3*3*3=9*3=27

4*4*4=16*4=64

5*5*5=25*5=125

(27*64)-125

1728-125

1603

7 0
3 years ago
Read 2 more answers
Please answer i need help
musickatia [10]

Answer:

use propotional theorem

8 0
3 years ago
Sam creates a game in which the player rolls 4 dice. What is the probability in this game of having at least 2 of the dice land
xxTIMURxx [149]

<em>*100% Correct answers</em>

Question 1

A surgical technique is performed on 10 patients. You are told there is an 80% chance of success. Find the probability that the surgery is successful for exactly 6 patients.  

0.088

Question 2

Sam creates a game in which the player rolls 4 dice. What is the probability in this game of having at least 2 of the dice land on 5.  

0.13101963141  

Question 3

Katie creates a game in which 3 dimes are flipped at the same time.  

5 points are awarded if all 3 dimes land on tails, but no points are awarded for anything else. What is the probability of not getting any points? (Hint: Find the complement).  

0.875

5 0
3 years ago
Read 2 more answers
Perimeter and area of a rectangular figure has a perimeter of 34cm its length is 9cm​
Artemon [7]

Answer:

Perimeter of rectangle = 32

Step-by-step explanation:

32 = 2(L+B)

L+B=16

B=16-L

B=16–9

B=7

AREA = L*B

AREA = 63sq.cm

5 0
3 years ago
An electronics company just finished designing a new tablet computer and is interested in estimating its battery-life. A random
Alika [10]

Answer:

6 \pm 2.861(0.3354)

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.861.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.861\frac{1.5}{\sqrt{20}} = 2.861(0.3354)

In which s is the standard deviation of the sample and n is the size of the sample.

The format of the confidence interval is:

S_{M} \pm M

In which S_{M} is the sample mean

So

6 \pm 2.861(0.3354)

7 0
3 years ago
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