3 years ago

WHOEVER CAN ANSWER AT LEAST 2 GETS BRAINLIEST!!

1 answer:

8 0

Answer:

Step-by-step explanation:

Could you type out #2?

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Where are the options

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Varvara68 [4.7K]

Answer:

The center of circle is $(0,0)$

Step-by-step explanation:

We need to find the center of the circle of the equation $x^{2}+y^{2}=4$

Since, the general equation of circle is $(x-h)^{2}+(y-k)^{2} = r^{2}$

Where (h,k) is center of circle and r is radius.

Re-write the circle equation is $x^{2}+y^{2}=4$ as,

$x^{2}+y^{2}=2^{2}$

Compare $x^{2}+y^{2}=2^{2}$ with $(x-h)^{2}+(y-k)^{2} = r^{2}$

so, $(x-0)^{2}+(y-0)^{2} = 2^{2}$

Hence, the center of circle is $(0,0)$

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Eva8 [605]

Answer:

1/2

Step-by-step explanation:

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