Three roads intersect to form a large triangular area as shown below.
2 answers:
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Option C:
The last two terms given of the standard polynomial are:
This shows 2 patterns to us:
r 's degree is increasing per term in the given polynomial.
s 's degree is decreasing per term in the given polynomial.
The sum of powers of variates r and s is 2+4 = 3+3 = 6.
And since standard polynomial, the same pattern must be present in all terms of the series.
All options except C are not valid.
Option C has term for which r's degree plus s's degree is 1 + 5 = 6.
And r's degree 1 < s's degree 5.
Thus its a valid term to be putted as first term in standard form of polynomial in consideration.
Thus Option C: is the needed expression.
Learn more here:
Answer:
x²-10x+25
Step-by-step explanation:
f(x) = x²
<h3>i) substitute the x-5 into x</h3>f(x-5) = (x-5)²
<h3>ii) using the formula (a-b)² = a²-2ab+b², expand the expression</h3>f(x-5) = (x-5)²
= x²-2(5x)+5²
<h3>iii) calculate the products</h3>f(x-5) = x²-2(5x)+5²
= x²-10x+25
* the pic i inserted shows the shape of your graph
