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Leni [432]
3 years ago
13

PLEASEE I NEED HELP I WILL GIVE BRAINLIST :))) ( btw im dump)

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

Step-by-step explanation:

u know u can download math go and u just take a picture and it will give u the answer

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(3xy^3)^2 (xy)^6 simplify the expression
solong [7]
9x8y12 it a lot of work to do so I don't want to type how to do the problem
5 0
3 years ago
Given the linear equation 3x + y = 5, find the slope of its graph
umka2103 [35]

Answer:

B) -3

Step-by-step explanation:

1. First you have to write the equation in slope intercept form. To do that, you must have y be alone on one side.

2. move the 3x to the right side with the 5 by subtracting 3x from both sides. Since 3x will cancel on the left, y will be left alone. y=-3x+5

3. Now that you're in slope intercept form, you can find the slope easily. The slope will always be the number in front of x. In this case, the number in front of x is -3. Therefore, -3 is your slope!

7 0
3 years ago
Read 2 more answers
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
4 years ago
Segment XY bisects angle WXZ and angle mZXY = 37 degrees. Find angle mWXY and angle mZXW
Vadim26 [7]

we know that

The angle bisector, is the line or line segment that divides the angle into two equal parts.

So

in this problem

m∠ZXW=m∠WXY+m∠ZXY

m∠WXY=m∠ZXY

Part a) <u>Find the value of m∠WXY</u>

m∠ZXY=37°-----> given value

so

m∠WXY=m∠ZXY=37°

therefore

<u>the answer part a)</u>

The measure of angle WXY is equal to 37°

Part b) <u>Find the value of m∠ZXW</u>

m∠ZXW=m∠WXY+m∠ZXY

m∠ZXW=37°+37°=74°

therefore

<u>the answer part b) is</u>

the measure of angle ZXW is 74 degrees

8 0
3 years ago
Use the figure to find the radius.
BlackZzzverrR [31]
The answer is 4 (four)
3 0
3 years ago
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