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3 years ago

PLEASEE I NEED HELP I WILL GIVE BRAINLIST :))) ( btw im dump)

Mathematics

1 answer:

Keith_Richards [23]3 years ago

7 0

Step-by-step explanation:

u know u can download math go and u just take a picture and it will give u the answer

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A spinner is divided into 10 congruent sections.Each section is labeled with a number as shown.What is the probability that the

Rufina [12.5K]

Answer:

50%

Step-by-step explanation:

The only numbers that are multiples of 2 are all even numbers. From 1 to 10 there are a total of 5 even numbers, meaning that only 5 sections are multiples of 2. Therefore, the probability of the arrow landing in a section that is labeled with a number that is a multiple of 2 would be

5/10 if we simplify this it would be 1/2 or 50%

Finally, we can say that the probability of the arrow landing on one of these sections is 50%

8 0

3 years ago

Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in <span>in burrows per square kilometer
</span> $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>

5 0

3 years ago

Determine the second derivative evaluated at t=0

enyata [817]

$M(t) = e^{3(e^t-1)}$

then using the chain rule, we have

$M'(t) = e^{3(e^t-1)} \times 3e^t = 3e^{3(e^t-1)+t}$

$M''(t) = 3e^{3(e^t-1)+t} \times (3e^t+1)$

Then

$M''(0) = 3e^{3(e^0-1)+0} \times (3e^0+1) = 3e^0 \times (3+1) = \boxed{12}$

3 0

3 years ago

HELP ME OUTT PPL (BRAINIEST)

Annette [7]

Answer:

(0, 6)

Step-by-step explanation:

Point T is at (3, 4), and three units to the left would be (0, 4). They then tell us to go two points up, which would change the ordered pair to (0, 6).

I hope this was helpful! Have a lovely day! :D

3 0

2 years ago

You are offered a job that pays $43 comma 000 during the first year, with an annual increase of 5% per year beginning in the

sveta [45]

49,778 would be earned on the 4th year

4 0

3 years ago