All the spheres on earth overlap with each other so that any changes occur in one sphere may affect the other.
<u>EXPLANATION: </u>
The four spheres of earth are Land (the lithosphere), water (hydrosphere), air (atmosphere), living things (biosphere). The living organisms receive sunlight, heat, and gases from the atmosphere and water from the hydrosphere.
All these spheres are interlinked with one other and assembles in a single location at the time of overlapping. Life would not be there on earth if all these spheres do not interact or overlap with each other.
Examples of the earth overlapping is given below;
- Birds the living organism that flies in the air.
- Water flows through the soil on land.
- Evaporation of water into the atmosphere causes rain on the land.
<span>1.Fold Mountains (Folded Mountains)
2.Fault-block Mountains (Block Mountains)
<span>3.Dome Mountains</span></span>
Answer:
I believe you just answered it yourself. they development an immunity to insecticides the more they are exposed to it.
Answer:
Function of each male reproductive system-
They produce, maintain and transport sperm and semen . They discharge sperm into the female reproductive tract. They produce and secrete male sex hormones.
Function of each female reproductive system-
The ovaries produce the egg cells, called the ova or oocytes. The oocytes are then transported to the fallopian tube where fertilization by a sperm may occur.
Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
