In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Step-by-step explanation:
f/p = p(1+i)^n
p= 2500
i=0.03 =3%
n=4
2500(1 + 0.03)^4
Answer:
Options (1), (5), and (6)
Step-by-step explanation:
See attached image
Divide both sides by <span>t
</span>
<span>a+b=r/t
</span>Subtract b <span>from both sides
</span>
a<span>=r/t-b = Solution </span>
Answer:
I have no idea
Step-by-step explanation:
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