Answer:
hi there ☺️
Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
pls rate me the brainiest
The answer to your question is 405
Answer:
d
Step-by-step explanation:
So the problem states,
52 = 36 + 4x
16 = 4x
x = 4 (must be less than or equal to)
Hey there!
Just do PEMDAS
• Parentheses
• Exponents
• Multiplication
• Division
• Addition
• Subtraction
3 + 1(6 ÷ 2)
= 3 + 1(3)
= 3 + 3
= 6
Therefore, your answer is: 6
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
