What is the volume of a box 24 1/4 inches long 18 inches wide and 24 inches tall

I need help finding the mean, median, and mode(s) I need help with number 7

natta225 [31]

Answer:

the mean is 57.5 the median is 44.5 and the mode is 47

Step-by-step explanation:

the mode is 47 cuz it appeared twice. the median is 57.5 bc 47+147+24+47+38+42=345 and 345/6 is 57.5

7 0

3 years ago

Explain how you got the answer

Gnoma [55]

Answer:

$\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }$

Step-by-step explanation:

<u><em>Given equation is</em></u>

$x^2 + y^2 -6x-6y -42 = 0$

Adding 42 to both sides

$x^2 + y^2 -6x-6y = 42\\$

Completing squares

$x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42$

Adding (3)² => 9 and (3)² => 9 to both sides

$(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2 (y-3)^2 = (2{\sqrt{15})^2}$

Comparing it with $(x-h)^2+(y-k)^2 = r^2$ where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = $2\sqrt{15}$

7 0

4 years ago

Ms.Smith has 28 sixth graders and 42 seventh graders for math. If she wants to break the two grades into identical groups withou

Zinaida [17]

Add the 28 and 42
then divide by 2
there should be 35 kids in group

4 0

3 years ago

Help me plz i want help plz

netineya [11]

Answer:

384

Step-by-step explanation:

6 squares of 8x8=

8x8x6=384

8 0

3 years ago

Read 2 more answers

We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental

mr Goodwill [35]

Answer:

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=1.1$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=51-1=50$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

8 0

3 years ago