Answer:
4 consecutive odd numbers are 111, 113, 115 and 117.
Step-by-step explanation:
Let the first odd number be x.
So the next odd number will be (x+2)
and the next two consecutive odd numbers are (x+ 4) and (x+6)
According to question,
The sum of all four odd consecutive numbers = 456
⇒ x + (x+ 2) + (x+4) + (x+6) = 456
or, 4x + 12 = 456
⇒ 4x = 456 - 12 = 444
⇒ x = 444/4 = 111
Hence, the first odd number = 111
Second odd number = 111+ 2 = 113
Third odd number is x + 4 = 111 + 4 = 115
And last odd number is x + 6 = 111 + 6 = 117
So, 4 consecutive odd numbers are 111, 113, 115 and 117.
Answer: d, p = 0.4493
Step-by-step explanation: this question is solved using a possion probability distribution because the event is occurring at a fixed rate.
For this question of ours the fixed rate is the fact that 12 customers visiting the shop within 15 minutes.
For this question our fixed rate (u) = 12/15 = 0.8
The probability distribution for possion is given as
P(x=r) = (e^-u * u^r) / r!
At this point x = 0 ( no customers coming to the shop)
P(x=0) =( e^-0.8 * 0.8^0)/ 0!
P(x=0) = (e^-0.8 * 1)/1
P(x=0) = e^-0.8
P(x=0) = 0.4493
It's this graph. You didn't give me any options in the question.
Answer:
5/6
Step-by-step explanation:
x > 1
x = 2,3,4,5,6
( quantity of 2,3,4,5,6)/(total)
5/6
Answer:
25
Step-by-step explanation:
Count all the squares on the edge.
