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Bad White [126]
3 years ago
11

Which of the following graphs would represent the solution set for y > 4/5 x – 1?

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

It's this graph. You didn't give me any options in the question.

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Vehicle A has a final sale price of $25,000 at 5% interest and financing up to 60 months and vehicle B has a final sale price of
andrezito [222]

The calculation of the interest based on the price given shows that vehicle B has a lower interest.

<h3>How to calculate the price?</h3>

From the information given, vehicle A has a final sale price of $25,000 at 5% interest and financing up to 60 months. The interest will be:

= (25000 × 5 × 5)/100

= $6250

Vehicle B has a final sale price of $29,000 at 4% interest and financing up to 60 months. The interest will be:

= (29000 × 4 × 5)/100

= $5800

Therefore, the calculation of the interest based on the price given shows that vehicle B has a lower interest.

Learn more about price on:

brainly.com/question/1153322

#SPJ1

3 0
2 years ago
I don't know how to do this please help
AveGali [126]
5z>15-----subtract 2 on both sides
z>3----divide by 5
therefore, z must equal -10, or -4
8 0
3 years ago
Line L passes through the point (-1, 1) and is PARALLEL to the line shown here. An equation of line L is
Pachacha [2.7K]
The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
m = ( y2 - y1 ) / ( x2 - x1 )
then the slope of that line is equal to slope of line passing pooint ( -1 , 1)
then solve the y intercept of the line using
y = mx + b
where b is the y intercept
then you will have the equation of the line
5 0
3 years ago
Read 2 more answers
(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf
alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have 3^n coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of \frac{3^n}{3} = 3^{n-1} coins

Step 2: you narrow down to group of \frac{3^{n-1}}{3} = 3^{n-2} coins

Step 3: you narrow down to group of \frac{3^{n-2}}{3} = 3^{n-3} coins

...

Step n: Step 1: you narrow down to group of 3^{n-n} = 3^0 = 1coin

8 0
3 years ago
CAN SOMEONE PLEASE HELP ME SOLVE THIS I WILL GIVE U BRAINIEST PLEASE AND THANK YOU.!
Arisa [49]

Answer:

Step-by-step explanation:

SIMPLE 30 X 30

8 0
3 years ago
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