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Brums [2.3K]
3 years ago
8

1. For each of the following, indicate whether it is a question that involves permutations, combinations, or neither, and then a

nswer the question posed. Explain your reasoning.
a. How many ways can a coach choose two co-captains from 16 players in the basketball team?
b. In how many ways can seven questions out of ten be chosen on an examination?
c. Find the number of ways that 10 women in the finals of the skateboard street competition can finish first, second, and third in the X Games final.
d. A postal zip code contains five digits. How many different zip codes can be made with the digits 0–9? Assume a digit can be repeated.
Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

we are given some scenerios and we are to find out the total number of ways after mentioning permutations, combinations, or neither

a. How many ways can a coach choose two co-captains from 16 players in the basketball team?

Combination because both are having same position so order does not matter

16C2 = 120

b. In how many ways can seven questions out of ten be chosen on an examination?

Combinations because order of question does not matter.

10C7 = 10C3 = 120

c. Find the number of ways that 10 women in the finals of the skateboard street competition can finish first, second, and third in the X Games final.

Here order matters.  Hence permutation

10P3 = 720

d. A postal zip code contains five digits. How many different zip codes can be made with the digits 0–9? Assume a digit can be repeated.

Here repitition is allowed.  So neither permutation nor combination.

No of ways = 10^5

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3 years ago
Which expressions are equivalent? Select two answers.
professor190 [17]

Answer:

<h2>A, C</h2>

Step-by-step explanation:

The distributive property:

<em>a(b + c) = ab + ac </em>or<em> a(b - c) = ab - ac</em>

<em></em>

A.\\\\\dfrac{1}{5}(x-50)=\dfrac{1}{5}x-\left(\dfrac{1}{5}\right)(50)=\dfrac{1}{5}x-\dfrac{50}{5}=\dfrac{1}{5}x-10\\\\B.\\\\-\dfrac{1}{3}(3x+18)=\left(-\dfrac{1}{3}\right)(3x)+\left(-\dfrac{1}{3}\right)(18)=-\dfrac{3}{3}x-\dfrac{18}{3}=-x-6\\\\-x-6\neq\dfrac{1}{3}x-6

C.\\\\\dfrac{1}{2}(x+16)=\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)(16)=\dfrac{1}{2}x+\dfrac{16}{2}=\dfrac{1}{2}x+8\\\\D.\\\\\dfrac{1}{8}(8x+8)=\left(\dfrac{1}{8}\right)(8x)+\left(\dfrac{1}{8}\right)(8)=\dfrac{8}{8}x+\dfrac{8}{8}=x+1\\\\x+1\neq\dfrac{1}{8}x+1\\\\E.\\\\-\dfrac{1}{4}(x+2)=-\dfrac{1}{4}x+\left(\dfrac{1}{4}\right)(2)=-\dfrac{1}{4}x+\dfrac{2\!\!\!\!\diagup^1}{4\!\!\!\!\!\diagup_2}=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\-\dfrac{1}{4}x+\dfrac{1}{2}\neq-\dfrac{1}{4}x+2

4 0
3 years ago
What is the range of the function in the graph?
Anon25 [30]
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This is why the answer is the interval notation answer [0,\infty)
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8 0
4 years ago
Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution
Blababa [14]

Answer:

If you mean only one rational solution, the answer is

k_1 = 8, k_2 = -8

If you mean at least 1 rational solution, the answer is

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Step-by-step explanation:

4x^2 + kx + 4 = 0

Let's calculate the discriminant.

\Delta = b^2 - 4ac

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Now, remember that:

\text{If } \Delta > 0 : \text{2 Real solutions}

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\text{If } \Delta < 0 : \text{No Real solution}

Therefore, I will just consider the first two cases.

k^2 - 64 > 0

and

k^2 -64 = 0

\boxed{\text{For } k^2 - 64 > 0}

k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64}   \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)

\boxed{\text{For } k^2 - 64 = 0}

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3 years ago
Example 3
chubhunter [2.5K]

Answer:

We conclude that

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Step-by-step explanation:

Given

<1 and <2 form a linear pair

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To determine

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<u>Important Points about linear pair:</u>

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As

<1 and <2 form a linear pair

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In other words, angle 1 is 4 times the measure of angle ∠2.

Let the angle ∠1 be = x

As the angle 1 is 4 times the measure of angle ∠2, so

The angle 2 will be = 4x

As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so

x + 4x = 180

5x = 180

divide both sides by 5

\frac{5x}{5}\:=\:\frac{180}{5}

\:x=36^{\circ }

Thus, we conclude that

  • The angle ∠1 = x = 36°
  • The angle ∠2 = 4x = 4(36°) = 144°
4 0
3 years ago
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