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user100 [1]
2 years ago
14

Which statement is true regarding the functions of the graph?

Mathematics
1 answer:
gregori [183]2 years ago
4 0

Answer:

f(- 3) = g(- 3)

Step-by-step explanation:

f(x) and g(x) are equal at the point of intersection.

When x = - 3 , f(- 3) = - 4 and g(- 3) = - 4

Thus

f(- 3) = g(- 3)

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Show work please :: I forgot how to solve
Vesna [10]
40 pages = 80 minutes
210 pages = ? minutes
Well, take the first fact; 40 pages in 80 minutes and use it to find how many pages per minute.
40/80=1/2
1/2 pages = 1 minute
1 page = 2 minutes
210 pages = ? minutes
210*2=420
420 minutes = 7 hours
210 pages = 7 hours
Hope this helped :)
4 0
3 years ago
Select two ratios that are equivalent to 4:18
steposvetlana [31]

Answer:

2:9

Step-by-step explanation

4:18 divided by 2 is the lowest it can go so 4 divided by 2 is 2

18 divided by 2 is 9 so,

2:9

4 0
2 years ago
Read 2 more answers
810 songs; 130% increase
horrorfan [7]
To do 130% increase you multiply by 1.3 so you do 810 × 1.3 = 1053
4 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
What is the answer to this math equation? - 1 5/8 + 9 1/4
SIZIF [17.4K]
I think -4 something
4 0
2 years ago
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