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3 years ago

8

At a pet store, 3/8 of the total animals were dogs. of those dogs 2/7 were labrador dogs. what fraction of the total pets were l

abrador dogs?

1 answer:

9966 [12]3 years ago

7 0

Answer: 3/28

Step-by-step explanation:

Here we go, whenever you see the word "of" this mean to multiply

2/7 x 3/8 = 3/28

Answer: 3/28 .

I hope this help...

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-Dominant- [34]

Answer:

d

Step-by-step explanation:

cause

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there were 16 teams at a gymnastics meet. each team had 12 members. how many gymnastics participated in the meet.

prisoha [69]

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A game is being played with two players. There are 21 balloons and the player who pops the last balloon wins. One or two can be

34kurt

Answer:

be the second player, and always leave a multiple of 3 balloons

Step-by-step explanation:

In order to win, a player must force the other player to leave one or two balloons. To do that, the winning player must leave one more balloon than the maximum number that can be popped. That is, the winner will be the player who leaves 3 balloons,

Working backward, we find that the winner must leave a multiple of 3 after each turn. Since the starting number is a multiple of 3, the first player must lose if the second player plays optimally.

The winning strategy is ...

be the second player
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4 0

3 years ago

Eric's notebook has 30 pages. he wants to writes a number on each page. how many digits will he write when he numbers all the pa

Roman55 [17]

The answer is d (i.e. 51).
the first 9 pages utilize 9 digits. the remaining 21 pages utilize two digits number. Therefore,
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3 years ago

Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFractio

nasty-shy [4]

Answer:

$\frac{13-7\sqrt{3}}{2}$

Step-by-step explanation:

We need to rationalize the denominator of $= \frac{5-\sqrt{3}}{4+2\sqrt{3}}$ . For rationalizing we multiply the equation by $\frac{4-2\sqrt{3}}{4-2\sqrt{3}}$

So, solving

$= \frac{5-\sqrt{3}}{4+2\sqrt{3}}*\frac{4-2\sqrt{3}}{4-2\sqrt{3}} \\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{4+2\sqrt{3}*4-2\sqrt{3}}\\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{(4)^2-(2\sqrt{3})^2}\\= \frac{5(4-2\sqrt{3})-\sqrt{3}(4-2\sqrt{3})}{16-(4*3)}\\=\frac{20-10\sqrt{3}-4\sqrt{3}+2*3}{16-12}\\=\frac{20+6-14\sqrt{3}}{4}\\=\frac{26-14\sqrt{3}}{4}\\= \frac{2(13-7\sqrt{3})}{4}\\=\frac{13-7\sqrt{3}}{2}$

5 0

3 years ago