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amid [387]
2 years ago
15

While shopping at the school bookstore, Ric purchased 4 book covers for $1.25 each , and a pen that cost 2/5 as much as the book

cover. What amount of change did Ric receive if he paid for his purchase with a $10 bill.
Mathematics
2 answers:
Novosadov [1.4K]2 years ago
5 0
Ric received $3.00 of change. First, you multiply 4 by $1.25 to get $5.00. Then, the pen cost $2.00 because 2 is 2/5 of 5. Next, you add 2 and 5 together to get $7.00. Lastly, you subtract 7 from 10 ($10.00-$7.00) to get your change, $3.00. Hope it helps :)
Ugo [173]2 years ago
4 0

Answer:

$3:00

Step-by-step explanation:

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Step-by-step explanation: A straight angle is 180°

180°- 120° = 60°

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Megan and Lily each pay $750 a month for the apartment they share. Kevin lives by himself and pays 1.8 times as much rent a mont
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2 years ago
Papa john is 50 years old. His age is 2 years more than 3 times the age of jimmy John
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Jimmy John is sixteen
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3 years ago
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emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
2 years ago
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
PIT_PIT [208]
The probability of having a 17 is the number of ways of having 17 divided by the number of different possible outcomes.

Ways of having 17:

Die 1     Die 2     Die 3    sum
6            6            5          6+6+5 = 17
6            5            6          6+5+6 = 17
5            6            6          5+6+6 = 17

Those are the only 3 possibilities of having 17 (you can only loose 1 point).

The total number of outcomes are 6*6*6 = 216

So the chances (probability) to win is 3 / 216 = 1/72 = 0.0139 
8 0
3 years ago
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