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amid [387]
3 years ago
15

While shopping at the school bookstore, Ric purchased 4 book covers for $1.25 each , and a pen that cost 2/5 as much as the book

cover. What amount of change did Ric receive if he paid for his purchase with a $10 bill.
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
5 0
Ric received $3.00 of change. First, you multiply 4 by $1.25 to get $5.00. Then, the pen cost $2.00 because 2 is 2/5 of 5. Next, you add 2 and 5 together to get $7.00. Lastly, you subtract 7 from 10 ($10.00-$7.00) to get your change, $3.00. Hope it helps :)
Ugo [173]3 years ago
4 0

Answer:

$3:00

Step-by-step explanation:

You might be interested in
Kevin bought 3 dvds for 45.99 how much would 7 dvds cost?
Alecsey [184]

Answer:

I am pretty sure the answer would be $107.31. Sorry if I'm wrong.

Step-by-step explanation:

First you take the total of the 3 DVD's (45.99) and you divide that by 3 (number of DVD's) to get 15.33 which is called the unit price. Then, you take your unit price and multiply that by how many items you are going to buy.

45.99 / 3 = 15.33

15.33 x 7 = 107.31

6 0
3 years ago
Joshua orders pictures from a photographer. Each picture costs $12.75. A one-time shipping fee of $3.25 is added to the cost of
Alik [6]

Answer:

6 pictures

Step-by-step explanation:

Let x be the number of pictures that was bought

Let y be the total amount of money collected for the picture

y= 3.25+12.75

3.25+12.75x= 79.75

Therefore x can be calculated as follows

12.75x= 79.75-3.25

12.75x= 76.5

x= 76.5/12.75

= 6

Hence Joshua ordered 6 pictures

5 0
3 years ago
Which price choice has the lowest unit price per ounce? (5 points) Choice A: 6 ounces of chocolate chips for $2.49. Choice B: 8
leonid [27]
2.49/6 = 0.415
3.32/8 = 0.415

unit rates are equal :)
4 0
4 years ago
Read 2 more answers
A nut-raisin mix costs $5.26 a pound. Rashid buys 15.5 pounds of the mix for a party. Rashid’s estimated cost of the nut-raisin
Verdich [7]

Answer:

D.$80

Step-by-step explanation:

$5.26 x 15.5= $81.53

The closest amount to $81.53 is D.$80

7 0
3 years ago
Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid
Gnom [1K]

Answer:

The area of the triangle is A=\sqrt{\frac{4027}{2}}

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

A=\frac{1}{2}||{\bf u} \times {\bf v} ||

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

{\bf AB} and {\bf AC}

The vector {\bf AB} is the difference of point B minus point A

{\bf AB}=(5-3,5-5,0-9)=(2,0,-9)

and the vector {\bf AC} is the difference of point C minus point A

{\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)

Next we need to find the cross product of this vectors.

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

This is the definition of cross product of two vectors in space:

Let {\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k} and {\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k} be vectors in space. The cross product of {\bf u} and {\bf v} is the vector

{\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}

Applying this definition we get

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}

||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}

The area of the triangle is

A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}

7 0
4 years ago
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