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BlackZzzverrR [31]
2 years ago
5

Which conic section is represented by the following equation?

Mathematics
2 answers:
lapo4ka [179]2 years ago
7 0

Answer:

A. circle

Step-by-step explanation:

andre [41]2 years ago
4 0

Answer:

circle

Step-by-step explanation:

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Help omg if so thank you.
Goshia [24]

Answer:

35

Step-by-step explanation:

49*5/7

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3 years ago
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The model shown represents which of the following?
-BARSIC- [3]

Answer:

its 3

Step-by-step explanation:

selcet 3 it goes plus 3 then back to neg 4 its the 3rd option

4 0
3 years ago
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Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
Determine if the sequence (cosn/ n) converges or diverges. tell if it is absolutely or conditionally convergent
nevsk [136]
. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2. 

Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.<span>by comparison test since cosn/n <= 1/n is convergent and 1/n is divergent by harmonic series so the series is conditionally converget </span>
4 0
3 years ago
Brainliest goes to whoever answers correctly also if you want more points then answer my others
Drupady [299]

Answer:

It is a value that is an abnormal distance from the other values in a data set.

Step-by-step explanation:

An outlier is something that stands out from another thing. Such as color in a black and white film.

7 0
2 years ago
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