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2 years ago

Find the mode for the scores 3,760, 5,200, 8,750, 4,400, 5,250

Mathematics

1 answer:

V125BC [204]2 years ago

3 0

Answer:

no mode

Step-by-step explanation:

no number appears more than once

therefore there is no mode

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HURRY PLEASEEEEE I RLLY NEED THIS

ira [324]

Answer:table 1 would be y=x-3 and table 2 is y=x-5

Step-by-step explanation:

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3 years ago

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Pls helppppppppppppp

Galina-37 [17]

Answer:

Determining the height of a cylinder given volume and radius

Step-by-step explanation:

For a right circular cylinder:

$v = \pi {r}^{2} h$

6 0

1 year ago

The city has an average of 13 days of rainfall for April.

zhenek [66]

Using the Poisson distribution, we have that:

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

For this problem, the mean is given as follows:

$\mu = 13$

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859$

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0$

$P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003$

$P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019$

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

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6 0

1 year ago

1. A construction company is planning to bid on a building contract. The

levacccp [35]

<u>Answer:</u>

The expected value of construction company is $30500.

<u>Solution:</u>

Given, A construction company is planning to bid on a building contract.

The bid costs $1,500 and has an 80% chance of being accepted.

If accepted, the company will receive $40,000 dollars.

We have to find the expected value.

We know that,

Expected value = probability $\times$ amount gained by bidding – bid amount

Expected value = 80% x 40000 – 1500

Expected value = 0.8 x 40000 – 1500

Expected value = 32000 – 1500

Expected value = 30500

Hence, the expected value is $30500.

8 0

2 years ago

I need someone to answer this question the answer choices are below

olga nikolaevna [1]

Answer:

The answer is A, 18.84.

Step-by-step explanation:

The two points are 6 places apart, so that can be 6 units as radius. To find the circumference of a circle you do r x 3.14 (to abbreviate pi). 6 x 3.14 is 18.84 so A is your answer.

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2 years ago

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