The optimum shape of such a box is half a cube. The corresponding cube will have a volume of 2×256 ft³ = 512 ft³ = (8 ft)³. Such a box has a square base that is 8 ft on a side. If the height is half that of the cube, it will be 4 ft.
The dimensions of your box will be 8 ft square by 4 ft high.
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If the base dimension is x ft, the area (quantity of material) is
... a = x² + 4x(256/x²)
... a = x² + 1024x⁻¹
Then the derivative of area with respect to x is
... a' = 2x -1024x⁻²
Setting this derivative to zero and solving for x gives the value of x for minimum area.
... 0 = 2x -1024/x²
... 512 = x³
... x = 8 . . . . . . . . same as above.
A.
If you roll up the quarter circle and cap the open end with the smaller circle, the resulting shape should be a cone.
It should be b let me know if im right
Answer:
y = -2/3x - 13
Step-by-step explanation:
The slope remains the same, but the y-intercept changes to -13
12
2 multiplied by 6 is 12 and so 1 multiplied by something is 12
Hope this helps.
