Day 1 and Day 3 his score add up to zero.
Day 2 and Day 4 his score add up to zero.
Answer:
The answer to the problem is C
The domain is all x-values.
The range is all y-values.
Domain: 3, 5, -3, 2, 1
Range: 4, 7, 8, 0, 3
Best of Luck!
x-intercept = (15, 0) y-intercept = (0, 3)
slope (m) = (y₂ - y₁)/(x₂ - x₁) = (0 - 3)/(15 - 0) = -3/15 = -1/5
Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is one of the given points
y - 0 = (-1/5)(x - 15)
-5y = x - 15
x + 5y = 15
Answer: x + 5y = 15
Answer:
The correct answer B) The volumes are equal.
Step-by-step explanation:
The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

which when evaluated gives 4pi/3.
Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.