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3 years ago

What is a double bar line

2 answers:

6 0

It is used to denote certain kind of norms in maths. (e.g: ║x║, ║x²║).It's also used to denote parallel lines. And this notation,║A║ is reserved to matrix. Hope it helps.

pshichka [43]3 years ago

3 0

Hi there so you were wondering what a double bar line is so i am gonna tell you a double bar line is <span>Answer a double bar line is what music is played on please chose me as best thanks :) always wanting to help you </span>

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Can someone please help me with question 35?

Genrish500 [490]

First you would find the area of the triangle which would be 84×92 then divide that answer by 2.
Then you will find the area of the circle using the given radius 20.5.
Lets work it out.
84×92=7728
7728÷2=3864 ft²
3864 ft² is the area of the backyard including the pool.
A=pi(20.5)²
A=1320.25 ft²
1320.25 ft² is the area of the pool.
Now we have to subtract to get the area of the backyard without the pool.
3864-1320.25=2543.75 ft²
2543.75 ft² is your answer.
Hope This Helps and God Bless!

8 0

4 years ago

Please help me im gonna have to do this over again if i get it wrong

frez [133]

<h2><u>✎ </u><u>Answer:</u></h2>

<u /> $1\frac{1}{2}$ $batches$

➛➛➛➛➛

$\frac{1/2}{1} =\frac{3/4}{x}$

$\frac{1}{2} =\frac{3}{4x}$

$cross~multiply$

$4x=2(3)$

$\frac{4x}{4} =\frac{6}{4}$

$x=\frac{3}{2} =1\frac{1}{2}$

<h3>✂----------------</h3><h3>hope it helps...</h3><h3>have a great day!!</h3>

3 0

3 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

3 years ago

Can someone help me with this math

irga5000 [103]

Answer:

1) is 3.32

Step-by-step explanation:

...........

5 0

3 years ago

Mark did 2/5 of a job and Alan did 1/3 of the remainder. The fraction of the job left undone

Evgesh-ka [11]

2/5=4/10=12/30 1/3=10/30 12/30+10/30=22/30 22/30=11/15

4 0

3 years ago