2 years ago

Plz

Mathematics

1 answer:

allsm [11]2 years ago

4 0

Top box is 2x
bottom box is 3

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3 years ago

Determine the length of the longest metal rod which could be stored in a rectangle box 20 cm by 50 cm by 30 cm.

navik [9.2K]

Answer:

61.64 cm

Step-by-step explanation:

The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:

$\therefore \: length \: of \:metal \: rod \\ = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ = \sqrt{ {20}^{2} + {50}^{2} + {30}^{2} } \\ = \sqrt{400 + 2500 + 900} \\ = \sqrt{3800} \\ = 61.64414 \\ = 61.64 \: cm$

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Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

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Finally $2cosecA$

I really hope this helps coz it took much time

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