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Thepotemich [5.8K]
3 years ago
6

Plz

Mathematics
1 answer:
allsm [11]3 years ago
4 0
Top box is 2x
bottom box is 3
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:( I Need help! Show work please! Aviva has a total of 52 coins, all of which are either dimes or nickels. The total value of th
Jet001 [13]

Answer:

42 Dimes, 10 Nickels.

Step-by-step explanation:

Dimes are worth $0.10, nickels are worth $0.05.

If D = number of dimes, and N = number of nickels, then the following equations are true:

0.10D + 0.05N = 4.70

D + N = 52

Next, let's multiply the first equation by 10 so that we can subtract the second one from it.

D + 0.50N = 47

(-) D + N = 52

Subtracting the second equation from the first one gives:

-0.5N = -5

-0.5N/-0.5 = -5/-0.5

N = 10

Finally, substitute N in the original second equation to find D.

D + 10 = 52

D + 10 - 10 = 52 - 10

D = 42

5 0
3 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
A music sharing service has an initial fee of $25 and a monthly fee of $6. When a person joins the service, it costs the company
STALIN [3.7K]

Answer: 25+6m > 70

Step-by-step explanation:

Let m = Number of months

Combined charges for music sharing service = 25+6m

Cost of joining to company = $70

According to the question,

Combined charges > Cost of joining to company  (To find number of months it would take for this)

25+6m > 70 (required inequality)

3 0
3 years ago
The radius of circle A is 4 times greater than the radius of circle B. Which of the following statements is true?
Black_prince [1.1K]

Answer:

Correct answer: C.  Ca = 4 Cb

Step-by-step explanation:

Given: Ra = 4 Rb

Ca : Cb = ?

Using the following formula to calculate the circumference of a circle:

C = 2 R π

Cb = 2 Rb π

Ca = 2 Ra π = 2 ·( 4 · Rb) · π = 4 · (2 Rb π) = 4 · Cb

Ca = 4 · Cb

God is with you!!!

3 0
3 years ago
If V is the midpoint of and W is the midpoint of , then what is VS?4 units8 units10 units20 units
Bess [88]
Is this on a graph if so you need to explain futher
6 0
3 years ago
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