All categories

3 years ago

Hey can I get the answer key for this I don't understand

Mathematics

2 answers:

stiv31 [10]3 years ago

8 0

Answer:

....

Step-by-step explanation:

1.weights

2.coach

3.Olympics

4.stadium

5.finish line

6.gold medal

7.swimming pool

8.team

9.first place

21.starting line

11.score

12.medal

13.athlete

14.trophies

ahrayia [7]3 years ago

5 0

Answer: i dont have the answer key but i did answer them for you

Step-by-step explanation:

You might be interested in

What is the ratio 9 1/2 to 12 2/3

vivado [14]

_ 9.5:12.6 That is the answer, btw the 6 is repeating

3 0

4 years ago

If AC = 14, what is the measure of AD? Round your answer to the nearest hundredth.

nikklg [1K]

Part A

Answer: Choice D) $\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}$

-----------------------------------------------

Explanation:

Let E be the intersection point of the diagonals. For any parallelogram, the diagonals bisect each other. This means that AE = EC = 2n+5 and it also means EB = DE = 4n-3

Focus on triangle AED. This triangle is a right triangle with angle AED as a 90 degree angle (any rhombus has its diagonals that are perpendicular to one another). The legs of this triangle are AE = 2n+5 and ED = 4n-3

Apply the pythagorean theorem to find hypotenuse AD

$(\text{leg1})^2+(\text{leg2})^2 = (\text{hypotenuse})^2\\\\(\text{AE})^2+(\text{ED})^2 = (\text{AD})^2\\\\(\text{AD})^2 = (\text{AE})^2+(\text{ED})^2\\\\\text{AD} = \sqrt{(\text{AE})^2+(\text{ED})^2}\\\\\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\$

This points to choice D as the final answer.

===========================================================

Part B

<h3>Answer: 7.07</h3>

-----------------------------------------------

Explanation:

If AC = 14, then half of this is AE = 7. The diagonals bisect each other, so they cut each other in half with E at the midpoint.

Since AE = 2n+5, we can solve for n like so

2n+5 = 7

2n = 7-5

2n = 2

n = 2/2

n = 1

Then we can find the length of AD

$\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\\text{AD} = \sqrt{(2*1+5)^2+(4*1-3)^2}\\\\\text{AD} = \sqrt{(2+5)^2+(4-3)^2}\\\\\text{AD} = \sqrt{7^2+1^2}\\\\\text{AD} = \sqrt{49+1}\\\\\text{AD} = \sqrt{50}\\\\\text{AD} \approx 7.0710678\\\\\text{AD} \approx 7.07\\\\$

Segment AD is roughly 7.07 units long. The other external sides of the rhombus (AB, BC and CD) are also this length because the four sides of any rhombus are the same length.

7 0

3 years ago

Find the solution of the ineuqality please.<br> -1/4(w-5) ≥ -2

Debora [2.8K]

Answer:

w<=13

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0

3 years ago

A random sample of 133 people was taken from a very large population. Sixty-five of the people in the sample were females.The st

rjkz [21]