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d1i1m1o1n [39]
3 years ago
12

Write the following phrase as an inequality: 3 more than twice n is at most 50.

Mathematics
2 answers:
Margarita [4]3 years ago
7 0

Step-by-step explanation:

3 more than twice n = 3+2n

3 more than twice n is atmost 50,

=> 3+2n <= 50 {(3+2n) is less than or equal to 50}

Natali [406]3 years ago
6 0

Answer:

3 + 2n ≤ 50

Step-by-step explanation:

"at most 50" means 50 or less.

Hope this helps.

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Could somebody answer this question please
Grace [21]
If m varies directly with x, then that means that you have to find the slope. To make it easier, m = y-variable, and x = x-variable.

Because you are trying to find your constant of variation (another word for slope, rate of change, etc.), the change of y over the change of x is your equation. in other words, divide your m variable by x.

When m = 60 and x = 6, you can set it up. 60 / 6 = k; and k = 10 when solved. Since 10 is not one of the answer choices listed in your answer key, I believe that your answer is NONE OF THE ABOVE.


I hoped this helped you.
5 0
3 years ago
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Angle 1 and angle 3 are ___ angles.
slega [8]

Angles 1 and 3 are vertical lines and because they are vertical, both angles equal each other.

4 0
3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
I dont get this question.
SashulF [63]
It is 12 - 2/3 = 18, then solve :)
hope that helps :D
8 0
4 years ago
Pls help^^^^ <br> i dont understand this hw
7nadin3 [17]

Answer:

h=6y/q∧3

Step-by-step explanation:

8 0
3 years ago
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