If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
C) 3/8
Step-by-step explanation:
Find 1/8 + 1/4
1/8 + 1/4
= 1/8 + 2/8
= 3/8
This is your perfect answer
Answer:
x=28
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
x+5+x−5=56
x+5+x+−5=56
(x+x)+(5+−5)=56(Combine Like Terms)
2x=56
2x=56
Step 2: Divide both sides by 2.
2x/2=56/2
x=28
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