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liq [111]
3 years ago
11

Please help :))) Find the area.

Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

a. 140 in²

Step-by-step explanation:

Find the area of triangle

1/2×10×6 = 30

The area of rectangle

10×11 = 110

Total of area = 30 + 110

= 140 in²

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Find x pretty please​
mario62 [17]

Answer:

100⁰

because this is a quadrilateral inscribed in the circle

=> x + 80 = 180

<=> x = 180 - 80 = 100⁰

3 0
3 years ago
What does the simple interest stand for? Interest = Principal x Rate x Time Interest = Per unit x Rate x Time Interest = Price x
ValentinkaMS [17]

9514 1404 393

Answer:

  (a)  Interest = Principal x Rate x Time

Step-by-step explanation:

The letters in the simple interest formula ...

  I = Prt

stand for ...

  Interest = Principal x Rate x Time

8 0
3 years ago
Line A passes through the points (10,6) qnd (2,15). Line B passes through the points (5,9) and (14,-1).
e-lub [12.9K]

Answer:

Line A equation = y=-9/8x+69/4

Line B equation = y=-10/9x+131/9

Step-by-step explanation:

7 0
3 years ago
I need help with this problem and if you can help me I would definitely appreciate it :)
Georgia [21]

Answer:

a. x=2, y=13

b. x=14, y=25

c. x=−4, y=13

Step-by-step explanation:

3 0
3 years ago
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
3 years ago
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