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3 years ago

1) y + 6 =20

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

Answer:

1. 14

2. 22

3. 3

4. 14

5. 10

6. 15

Step-by-step explanation:

1. 20-6=14

2. 22 bc it just is

3. 15-12

4. 16-2

5. 10+4

6. 5+10 is 15

This was too easy. Are these supposed to be trick questions.

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One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

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Step-by-step explanation:

Given

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Required

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Divide through by d

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A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

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So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

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