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Alekssandra [29.7K]

3 years ago

14

Your height and weight are examples of which level of measurement? A. Ordinal B. Nominal C. Ratio D. Interval

1 answer:

Ivahew [28]3 years ago

8 0

Answer:

C. Ratio

True for this case we have a clear definition of the 0 since the 0 for the heigth and the weigth represent absence of mass. And the differences between numerical values for the two variables are meaingful.

Step-by-step explanation:

We want to know which type of variable represent the weigth and the height. Let's analyze one by one the options given:

A. Ordinal

False since by definition an ordinal variable is "is a categorical variable for which the possible values are ordered". And for this case the height and the weigth are not categorical since represent quantitative data.

B. Nominal

False by definition and ordinal variable is which one that can't be represented by numeric values, and for this case the weight and the height are not example of this definition.

C. Ratio

True for this case we have a clear definition of the 0 since the 0 for the heigth and the weigth represent absence of mass. And the differences between numerical values for the two variables are meaingful.

D. Interval

False on this scale we don't have a clear definition of the 0. And for this case the heigth and the weight have a known definition of the 0 corresponding to the absence of mass. And since the ratios are meaingful for the heigth and the weigth then can't be an interval variable.

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storchak [24]

The value of d is -2

Step-by-step explanation:

The nth term of the arithmetic sequence is $u_{n}=u_{1}+(n-1)d$ , where

$u_{1}$ is the first term
d is the common difference between each 2 consecutive terms

The nth term of the geometric sequence is $u_{n}=u_{1}r^{n-1}$ , where

$u_{1}$ is the first term
r is the common ratio between each two consecutive terms $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∵ $u_{1}$ of an arithmetic sequence is 1

∵ The common difference is d, where d ≠ 0

∵ $u_{2}$ , $u_{3}$ , $u_{6}$ are the first 3 terms of a geometric sequence

∵ $u_{2}$ = 1 + (2 - 1)d

∴ $u_{2}$ = 1 + d

∵ $u_{3}$ = 1 + (3 - 1)d

∴ $u_{2}$ = 1 + 2d

∵ $u_{6}$ = 1 + (6 - 1)d

∴ $u_{2}$ = 1 + 5d

∴ The first 3 terms of the geometric sequence are (1 + d) , (1 + 2d) ,

(1 + 5d)

∵ The common ratio in the geometric sequence is $r=\frac{u_{2}}{u_{1}}=\frac{u_{3}}{u_{2}}$

∴ $r=\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

- Use cross multiplication with the equal fractions

∵ $\frac{1+2d}{1+d}=\frac{1+5d}{1+2d}$

∴ (1 + 2d)(1 + 2d) = (1 + d)(1 + 5d)

∴ 1 + 2d + 2d + 4d² = 1 + 5d + d + 5d²

- Add like terms in each side

∴ 1 + 4d + 4d² = 1 + 6d + 5d²

- Subtract 1 from both sides

∴ 4d + 4d² = 6d + 5d²

- Subtract 4d from both sides

∴ 4d² = 2d + 5d²

- Subtract 4d² from each side

∴ 0 = 2d + d²

- Take d as a common factor

∴ 0 = d(2 + d)

- Equate each factor by 0

∴ d = 0 but we will reject it because d ≠ 0

∴ 2 + d = 0

- Subtract 2 from both sides

∴ d = -2

The value of d is -2

Learn more:

You can learn more about the sequence in brainly.com/question/1522572

#LearnwithBrainly

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