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2 years ago

Another one another one...........

Mathematics

1 answer:

USPshnik [31]2 years ago

4 0

Answer:

Hope it helped you out

Tysm

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Find the length of arc ac in terms of pi

aniked [119]

=theta/360°×2pi ×r
theta=180-60=120°
r=24÷2=12

120/360 × 2 × 22/7 × 12=
1/3 × 2 × 22/7 × 12=
176/7=
25.14

3 0

3 years ago

Which expression defines the given series for seven terms?<br><br> 15 + 19 + 23 + . . .

dolphi86 [110]

The expression defines the given series for seven terms, i don't understand the question but i do know the sum which you should know to

15 + 19 + 23 = 57

Sorry

5 0

2 years ago

Read 2 more answers

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

2 years ago

Sin-1 (2/3) rounded to nearest 10th

Luda [366]

the is answer 2 because if u round it 3

6 0

3 years ago

What is the slope of a line y=7.8x+62

dexar [7]

Answer:

m = 7.8

Step-by-step explanation:

Its the slope. Its the number next to the x.

3 0

2 years ago