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Ksenya-84 [330]
3 years ago
5

7) Shannon is selling some embroidered jackets on a Web site. She wants 10 points

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Answer: A

Step-by-step explanation:

Nothing you a bum

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This table shows a linear relationship. x: 6 12 18 24 30 y: 252 504 756 1008 1260 Based on the information in this table, which
Anton [14]

Answer:

The difference between value of y at x=11 is 385, the correct option is third.

Step-by-step explanation:

The difference between value of y at x=11 is 385, the correct option is third.

The equation of a line which passing through two points is given below,

The two points from the table are (3,240) and (4,320), the equation is,

Put x=11

Therefore according to the table the value of y is 880 at x=11.

The two points from the table are (2,90) and (4,180), the equation is,

Put x=11,

Therefore according to the table the value of y is 495 at x=11.

The difference between the values of y at x=11 is,

Therefore third option is correct.

3 0
2 years ago
If you add 1 to half of 1, then half of 1 to the previous number, and so on, will you ever get to 2?
lisov135 [29]

Answer:

no

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Albert's hourly pay is $8.10. He has an hourly pay of $12.15 when he works more than 40 hours. He worked 45 hours last week. Wha
Sedaia [141]

Answer:

$384.75

Step-by-step explanation:

Albert's hourly pay is $8.10

When he works for more than 40 hours, his hourly pay will increase to $12.15.

Last week, Albert worked for 45 hours, his hourly pay would be:

First 40 hours = $8.10 * 40 = $324

Remaining 5 hours =

$12.15 * 5 = $60.75

Albert gross pay for this period will be calculated as:

$324 + $60.75 = $384.75

Therefore, Albert gross pay for this period = $384.75

3 0
4 years ago
Can anyone help me on this problem, please? It's from a section on literal equations.
Agata [3.3K]
If he charges $145 he worked for 5 hours at $20 an hour
4 0
3 years ago
Read 2 more answers
Solve by factoring c^2=5c
muminat
Hey there!

c² = 5c

Subtract 5c from both sides:

c² - 5c  = 5c - 5c

Simplify :

c² - 5c = 0

c = 5 , c = 0


6 0
3 years ago
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