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Lerok [7]
3 years ago
12

If |x-1| = |x+5|, find the value of x.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0

Greetings.

The answer is x = -2.

Explanation:

By solving the Absolute-Value Equation. We give them 2 conditions.

<em>When x ≥ 0 and When x < 0</em>

<em>The different is that When x ≥ 0, |x-a| = x-a as defined.</em>

<em>And when x < 0. |x-a| = -x+a as defined.</em>

( 1 ) - When x ≥ 0 for |x-1| and |x+5|

When x ≥ 0, |x-1| = x-1 and |x+5| = x+5

Therefore, x-1 = x+5

x-1=x+5\\x-x=5+1\\0=6

Because the equation is false. Therefore, The condition (1) doesn't apply.

( 2 ) - When x ≥ 0 for |x-1| and x < 0 for |x+5|

This time, we try another condition.

When x ≥ 0, |x-1| = x-1 and When x < 0, |x+5| = -x-5.

x-1=-x-5\\x+x=-5+1\\2x=-4\\x=-\frac{4}{2}\\x=-2

And we get the answer, |x-1| = |x+5| when x = -2.

But we haven't tried the last condition.

( 3 ) And that is when x < 0 for both terms.

|x-1| = -x+1 (x < 0)

|x+5| = -x-5 (x < 0)

-x+1=-x-5\\-x+x=-5-1\\0=-6

The equation is not true. Therefore, the answer is x = -2.

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3 years ago
What is the area of the toy bicycle wheel if the radius is 1 inch ?
dolphi86 [110]
Answer:
_________________________________________________________
1)  The area, in terms of "π" , is:  " <span>1π  in.² "  .
</span>__________________________________________________________
2)  The area, using the approximation of  "3.14"  for "π" , is:  " 3.14 in.²  " .
__________________________________________________________ 
Explanation:
__________________________________________________________
The formula/equation of the area of a circle, "A":
_______________________________________
A = π * r² ;
 
 in which π ≈ 3.14 ; 
               A = Area; 
               r = length of radius = 1 in. (given). 
______________________________________

  To find the area, take our known values, and plug them into the formula to find our answer:
_____________________________________
1)  To solve for the Area, in terms of "π" ;
_________________________________________
   
   A = π * r²  = π *(1 in.) ² = π * 1 in² ;
 
   A = 1π  in.²  .
____________________________________________________
2) To solve for Area, using the approximation of "3.14"  for "π"  :
___________________________________________________
   A = π * r² ;
 
   A ≈ (3.14) * (1 in.)²  =  (3.14) * (1²) * (in.²)  ;
      =  (3.14)*(1)*(in.²)  ;
_____________________________________________________
   A ≈  3.14 in.²
_____________________________________________________

8 0
3 years ago
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