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Annette [7]
4 years ago
5

3/8 of the seventh grade students were taking advanced math at the beginning of the year, but seven dropped out by the end of th

e year. If there were 140 students taking advanced math at the end of the year, how many seventh grade students are there?
Mathematics
1 answer:
Slav-nsk [51]4 years ago
6 0

Answer:

392 students

Step-by-step explanation:

Given: 3/8 of the seventh grade students were taking advanced math at the beginning of the year.

          Seven dropped out by the end of the year.

          There are 140 students taking advanced math at the end of the year.

Lets assume total number of students of seventh grade be "x".

As given, 3/8 of the seventh grade students were taking advanced math at the beginning of the year.

∴ Number of student took advanced maths at the beginning= \frac{3}{8} \times x= \frac{3x}{8}

We know, 7 student dropped out of advanced math by the end of the year.

Now, forming an equation to determine number of students taking advanced math at the end of the year.

⇒ \frac{3x}{8} -7= 140

Solving the equation  to find number of student in seventh grade.

⇒ \frac{3x}{8} -7= 140

Adding both side by 7

⇒ \frac{3x}{8} = 140+7

Multiplying both side by 8

⇒3x= 147\times 8

Dividing both side by 3

⇒x= \frac{147\times 8}{3}

∴ x= 392

Hence, there are 392 students in seventh grade.

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IceJOKER [234]

Answer:

8 hours 20 minutes

Step-by-step explanation:

Given that :

Time Rachel left for school = 7:45 a.m

Time she returned Home = 4:05 p.m

Time for which Rachael was gone :

4:05 p.m - 7:45 a.m

7:45 a.m to 3:45 p.m= 8 hours

3:45pm to 4:05 pm = 20 minutes

= 8 hours 20 minutes

Rachael was gone for 8 hours 20 minutes

8 0
3 years ago
3(2x-1) what is the anwser to this
Illusion [34]

Answer:

6x-3

Step-by-step explanation:

3(2x-1)

DISTRIBUTE

3*2x = 6x

3*(-1) = -3

6x-3

6 0
3 years ago
Find the x−and y−intercepts.
nadya68 [22]

Answer:

(4,-8/5)

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A box contains 10 balls, of which 3 are red, 2 are yellow, and 5 are blue. Five balls are randomly selected with replacement. Ca
VLD [36.1K]

Answer:

The required probability is 0.1.

Step-by-step explanation:

red balls = 3

yellow balls =  2

blue balls = 5

Selected balls = 5

Number of elemnets in sample space = 10 C 5 = 1260

Ways to choose 1 red ball and 4 other colours =  (3 C 1 ) x (7 C 4) = 105

Ways to choose 5 balls of other colours = 7 C 5 = 21

So, the probability is

\frac{105}{1260} + \frac {21}{1260}\\\\\frac{126}{1260}=0.1  

8 0
3 years ago
Find the generating function for the sequence 1,1,1,2,3,4,5,6,....
marin [14]

Answer:

P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1[/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

1,1,1,2,3,4,5,6,...

the generating function would be

P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\

we can multiply P(x) by x to get

xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...

Note that

P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\   \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)

which for \mid x \mid < 1 can be rewritten as

(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}

8 0
3 years ago
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