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Annette [7]
3 years ago
5

3/8 of the seventh grade students were taking advanced math at the beginning of the year, but seven dropped out by the end of th

e year. If there were 140 students taking advanced math at the end of the year, how many seventh grade students are there?
Mathematics
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer:

392 students

Step-by-step explanation:

Given: 3/8 of the seventh grade students were taking advanced math at the beginning of the year.

          Seven dropped out by the end of the year.

          There are 140 students taking advanced math at the end of the year.

Lets assume total number of students of seventh grade be "x".

As given, 3/8 of the seventh grade students were taking advanced math at the beginning of the year.

∴ Number of student took advanced maths at the beginning= \frac{3}{8} \times x= \frac{3x}{8}

We know, 7 student dropped out of advanced math by the end of the year.

Now, forming an equation to determine number of students taking advanced math at the end of the year.

⇒ \frac{3x}{8} -7= 140

Solving the equation  to find number of student in seventh grade.

⇒ \frac{3x}{8} -7= 140

Adding both side by 7

⇒ \frac{3x}{8} = 140+7

Multiplying both side by 8

⇒3x= 147\times 8

Dividing both side by 3

⇒x= \frac{147\times 8}{3}

∴ x= 392

Hence, there are 392 students in seventh grade.

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The perimeter of a rectangle is greater than or equal to 74 meters.
Ksju [112]

Answer:

12

Step-by-step explanation:

First, multiply the length by two then, subtract the total by the sum, last divide by two.

(25 * 2)

(74 - 50)

(24/2)

Answer = 12

5 0
3 years ago
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△HES ≅ △PBN, HE = 3.9 cm, SB = 0.9 cm, and NS = 4.5 cm<br><br> What is the length of ES ?
Natali5045456 [20]
 ns +sb = 5.4 cm

sb = en so en can be plugged in for sb

therefor es = 5.4
3 0
3 years ago
Marley had $495.66 in her bank account after she paid her monthly bills. She took her sister out to lunch, and paid $38.90. How
SOVA2 [1]

Answer: the answer is $456.76

Step-by-step explanation: All you have to do is subtract 38.90 from 495.66 and get your answer

5 0
2 years ago
The number of books sold over the course of the four-day book fair were 190, 100, 272, and 74. Assume that samples of size 2 are
g100num [7]

Answer:

the answer is below

Step-by-step explanation:

We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)

in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean

x1 x2 probabilityP(x1,x2) sample mean

190 190    1/16                 190

190 100    1/16                 145

190 272    1/16                 231

190 74    1/16                 132

100 190    1/16                 145

100 100    1/16                 100

100 272    1/16                 186

100 74    1/16                        87

272 190    1/16                 231

272 100    1/16                 186

272 272    1/16                 272

272 74    1/16                 173

74 190    1/16                 132

74 100    1/16                 87

74 272    1/16                 173

74 74    1/16                 74

Summarizing above with adding duplicate values

sample mean   probability

       74              1/16

      87               1/8

    100                1/16

    132                1/8

    145                1/8

    173                1/8

   186                1/8

   190               1/16

    231               1/8

   272               1/16

5 0
3 years ago
Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
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