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yuradex [85]
3 years ago
7

Please help 50 point !!

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

The last one

Step-by-step explanation:

x^3+1=0

Subtract 1 from both sides

x^3+1-1=0-1

<em>simplify</em>

<em />x^3=-1

\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

x=\sqrt[3]{-1},\:x=\sqrt[3]{-1}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{-1}\frac{-1-\sqrt{3}i}{2}

<em>simplify</em>

<em />x=-1,\:x=\frac{1}{2}-i\frac{\sqrt{3}}{2},\:x=\frac{1}{2}+i\frac{\sqrt{3}}{2}

<u>(That's basically the last one but in a different way of writing it)</u>

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