8× what =2

Jason Gomi has worked 42 hours this week. He worked in excess of 8 hours each day. His regular hourly wage is $10 per hour. What

mylen [45]

Answer:

$430

Step-by-step explanation:

According to current overtime pay laws, every hour worked over 40 weekly hours must be paid at a rate of 1.5 times the regular hourly rate. Jason Gomi has worked 2 hours of overtime, his gross wages for the week are:

$W = 40*\$10+(2*1.5*\$10)\\W=\$430$

Jason's gross wages for the week are $430.

6 0

4 years ago

. Denise has multiplied (2r – 3)(2r + 3) to get 4r2 – 9. After looking at her work, Hyder says her solution must be incorrect be

makvit [3.9K]

Answer:

The answer is 4r² – 9

Denise answer is correct.

Step-by-step explanation:

One of the methods of solving the given equation [(2r – 3)(2r + 3)] is the FOIL method

Using the FOIL method (Used for multiplying binomials)

F stands for first

O stands for outer

I stands for inner

L stands for last

In this method, it means we will first multiply the first terms followed by multiplying the outer term, then multiplying the inner terms and finally, the last terms.

So, for the equation (2r – 3)(2r + 3)

First : (2r)(2r) = 4r²

Outer : (2r)(+3) = 6r

Inner : (–3)(2r) = – 6r

Last : (–3)(+3) = – 9

Adding the results we get

4r² + 6r – 6r – 9 (+6r and – 6r cancels out)

= 4r² – 9

∴ (2r – 3)(2r + 3) = 4r² – 9

Hence, Denise answer is correct

5 0

3 years ago

Suppose A,B and C are 2 ×2 matrices , E,F and G are 3 × 3 matrices, H and K are 2×3 matrices and L and M are 3×2 matrices. For e

Alekssandra [29.7K]

Answer:

a) 2x2 b)3x3 c) Not possible d) 2x3 e) 3x2 f) 3x3 g)Not possible h)3x2

Step-by-step explanation:

-> we can only add matrices with same size

-> we can only multiply when columns of first equal to rows of second

-> nxm multiplied by pxq gives nxq eg 3x2 mul 2x2 gives 3x2

-> addition and mul by const number dont change the size

So considering the above facts :-

a) AB+C = [(2x2)(2X2)]+(2x2)=(2x2)+(2x2)=2x2

b) 3GF =3[(3x3)(3x3)]=3(3x3)=3x3

c)CK+B= [(2x2)(2x3)]+(2x2)=(2x3)+(2x2) which is not possible (see point 1)

d)CK+H =as CK is (2x3) so (2x3)+(2x3)=(2x3)

e)EMC=[(3x3)(3x2)](2x2)=(3x2)(2x2)=3x3

f)GLH=[(3x3)(3x2)](2x3)=(3x2)(2x3)=3x3

g)HLG=[(2x3)(3x2)](3x3)=(2x2)(3x3)= not possible(see point 2)

h)2EL+5MB=2[(3x3)(3x2)]+5[(3x2)(2x2)]=(3x2)+(3x2)=3x2

8 0

3 years ago

How long does it take a snail to crawl 81 inches

quester [9]

Answer:

5 hours just measured

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

C+ax=dx this one has all variables and no numbers

sergeinik [125]

That's OK, but you have not said which variable you want to solve it for.

To solve for 'x':
 c + ax = dx

Subtract c from each side: ax = dx - c

Subtract dx from each side: ax - dx = -c

Factor the left side: x (a - d) = -c

Divide each side by (a - d) : x = -c / (a - d) or x = c / (d - a) .

To solve for 'c': 
 c + ax = dx

Subtract ax from each side and factor: c = x (d - a) 

To solve for 'd': 
 c + ax = dx

Divide each side by 'x': d = c/x + a .

To solve for 'a':
 c + ax = dx

Subtract 'c' from each side: ax = dx - c

Divide each side by 'x': a = d - c/x .
.

6 0

3 years ago