$f(x)=x+1 \\g(x)=\dfrac{1}{x} \\(f\cdot g)(x)=(x+1)\dfrac{1}{x} \\(f\cdot g)(x)=\underline{\dfrac{x+1}{x}} \\ \\0=\dfrac{x+1}{x} \\0=\dfrac{x}{x}+\dfrac{1}{x} \\0=1+\dfrac{1}{x} \\-1=\dfrac{1}{x} \\-x=1 \\x=1$

4 0

2 years ago

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Subtract the two expressions. -y - 5 from 3y + 2

Naddik [55]

I believe that the answer would be 4y + 7

7 0

2 years ago

DROP AN ANSWERRRR!!!!!

nataly862011 [7]

Answer:

Step-by-step explanation:

8 0

2 years ago

The total cost C for p pounds of lithium if each pound costs $5.57

user100 [1]

here's an equation for the inequality:

5.57p = c

hope this helps :D

4 0

2 years ago