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3 years ago

3. Machine A packs 4, cartons in 5 hour.

Mathematics

1 answer:

grigory [225]3 years ago

3 0

Answer:

Machine B is the faster machine because it packs 4 cartons in an hour while the other machine takes 5 hours to pack 4 cartons. The faster machine can pack 4 cartons in an hour.

Step-by-step explanation:

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There is a bag filled with 4 blue and 5 red marbles.

kkurt [141]

Answer:

Step-by-step explanation:

There are 4 blue, 5 red and total of 9 marbles.

If two marbles are taken and we are looking for exactly one red, then it is:

red, then blue or blue, then red

Find the probability of each case:

P(r, b) = 5/9*4/8 = 5/18
P(b, r) = 4/9*5/8 = 5/18

Probability of exactly one red:

P = 5/18*2 = 5/9

6 0

2 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago

A triangle has a perimeter of 10a + 3b + 12 and has sides of length 3a + 8 and 5a + b what is the length of the third side ?

RideAnS [48]

Answer:

2a +2b +4

Step-by-step explanation:

The perimeter is the sum of the lengths of the three sides. If x represents the length of the third side, then ...

(3a +8) +(5a +b) +x = (10a +3b +12)

Subtracting from the equation everything on the left side that is not x, we get ...

x = (10a +3b +12) -(3a +8) -(5a +b)

= a(10 -3 -5) +b(3 -1) +(12 -8)

= 2a +2b +4

The length of the third side is 2a +2b +4.

5 0

2 years ago

My question is in the picture please help. First answer gets brainliest

Mandarinka [93]

Round 1 player 1 because 12 is the greatest number

5 0

2 years ago

Look at the sceenshot-- help??

Burka [1]

The answer is: 3.
_________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is: 3.
_______________________________________
Explanation: We are given that the ordered pair: "(3,10)" exists. In other words, when x = 3, y =10.
______________________________________
The "missing value" refers to the "empty box" in the table shown (in the attached screenshot). The "empty box" shows a "y-coordinate" of "20"; but a "missing" corresponding "x-coordinate".
____________________________________
The problem asks:
_________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is: ____?
___________________
The answer is: 3.
_______________________
We know the answer is "3"; because we know that "3" already has 1 (one) corresponding y-coordinate.

By definition, a "function" cannot have ANY "x-coordinates" that have more than one "corresponding y-coordinate". As such:
_______________________________________
In the table, the relation (x, y) is not a function is the "missing value" of "x" is:
____________
3.
____________
Additional information:
____________
When examining an equation on an actual graph, we can use what is called the "vertical line test". That is, one can take a pencil and vertically go through the "y-axis", or even examine it visually, to see if there are any "x-values" that have more than one corresponding "y-coordinate".
If no, then it "passes" the "vertical line test" and is a "function".
If not, then it does NOT pass the "vertical line test" and is NOT a function.
__________________________________________

4 0

2 years ago