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strojnjashka [21]
3 years ago
12

What’s the answer to this question??

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

31/100

Step-by-step explanation:

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What is the steps and answer to do this question -x-7y=9 -x+9y=-23
Hitman42 [59]
The answer is 23.

Good luck :)
7 0
3 years ago
Rewrite the following the form log (c) log (20) - log (5)
Dmitrij [34]

Answer:log (20/5)

Step-by-step explanation:

When subtracting logs you divide the numbers after the log

4 0
3 years ago
PLEASE HELP!!<br>Write an inequality, in slope-intercept form, for the graph below. ​
Bond [772]

Ok, so we know one point is (4,2) and the other is (-4, 0)

Slope: -2/-8 = 1/4

y ? 1/4x + b

0 = -1 + b

b = 1

y < 1/4x + 1

5 0
3 years ago
2) Which equation could represent a line that is perpendicular to y= -2x +<br> 4?
pshichka [43]

Answer:

Perpendicular lines have a slope that is the negative reciprocal of the given line.

For example, if a given line has the slope 3/2, the the perpendicular line would have the slope -2/3.

For the given line: y = 4x - 7, the perpendicular line would have a slope of -1/4

There isn't enough info in the question to determine the y-intercept. Literally, any y-intercept could work and the line would still be perpendicular. Is the line supposed to pass through a certain point?

Your answer would be something like: y = -1/4 x + b

b is the y-intercept...if your question paper is multiple choice, choose the answer with the slope of -1/4. If it's supposed to pass through a certain point (x,y) replace x and y with the values in that point and solve for b to get the y-intercept.

6 0
3 years ago
Read 2 more answers
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

4 0
3 years ago
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