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iren [92.7K]
3 years ago
12

Do you know this ?!?!!??!?!!!!!?!?

Mathematics
1 answer:
rjkz [21]3 years ago
8 0
Domain is [-2,2]
range is [-3,1)
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Collin solved the inequality:
valentinak56 [21]

Step-by-step explanation:

collin is correct and incorrect at the same time. when you solve this, you start with adding like terms.

10x and -11x will be added together to be -1x, after we figure this out, we solve.

-1x+7<-20

-7       -7

-1x<-27

/-1   /-1

x<27

after you solve, you notice that x is less than 27. collin has the correct answer for solving the equation, but if were looking on a more technical note, he would be incorrect because he said the answer is 27, when the answer is actually less than 27. therefore, collin has solved the inequality correctly, but he has said the answer incorrectly

6 0
3 years ago
What is 3141 times X. x=5783978
kirill115 [55]

Answer:

18167474898

Step-by-step explanation:

I used a calculator.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

4 0
3 years ago
Abiodun and taiwo share 735 naira between them so that abiodun get 95naira more than taiwo find how much money each gets
DerKrebs [107]

Answer:

Abiodun gets - <u>415 naira</u>

Taiwo gets -<u> 320 naira</u>

Step-by-step explanation:

Let us consider  x and y as Abiodun and Taiwo,

Therefore , acccording to the question , equation formed will be -

 x+y=735 naira ------ 1

and

x=y+95

x-y=95 ------2

From equation 1 and 2, we get

   2x=830

x=\frac{830}{2}

x=415 naira (that is Abiodun share)

now , Calculating Taiwo share from equation 1

x+y=735\\415+y=735

y=735-415

y = 320 naira (that is Taiwo share )

Therefore , Share of Abiodun = 415 naira

   Share of Taiwo = 320 naira

5 0
3 years ago
Can someone help me plz ​
bija089 [108]

Answer:

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4 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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