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Answer and explanation:
Given : Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are as follows :
Strength Strength
High Low
High conductivity 74 8
Low conductivity 15 3
To find :
a) If a stand is randomly selected, the probability that is conductivity is high and its strength is high
The favorable outcome is 74
The probability is given by,
b) If a stand is randomly selected, the probability that its conductivity is low or strength is low
Conductivity is low A= 15+3=18
Strength is low B= 8+3=11
Conductivity is low and strength is low
Probability is given by,
c) Consider the event that a strand low conductivity and the event that the strand has a low strength. Are these tow events mutually exclusive?
Since the events the stand has low conductivity and the stand has low strength are not mutually exclusive, since there exists some cases in which both the events coincide. i.e. Intersection of both the events exists with probability 0.03.
The formula of a lateral area of a cylinder:
We have r = 9 yd and H = 4 yd. Substitute:
Answer:
a. 2^(x-2) = g^(-1)(x)
b. A, B, D
Step-by-step explanation:
the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)
1. replace g(x) with y and solve for x
y = log₂(x) + 2
subtract 2 from both sides to isolate the x and its log
y - 2 = log₂(x)
this text is replaced by the second image -- it was marked as inappropriate
thus, 2^(y-2) = x
replace x with g^(-1)(x) and y with x
2^(x-2) = g^(-1)(x)
2. plug this in to points A, B, C, D, E, and F
A: (2,1)
plug 2 in for x
2^(2-2) = 2⁰ = 1 so this works
B: (4, 4)
2^(4-2) = 2²= 4 so this works
C: (9, 3)
2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work
(5, 8)
2^(5-2) = 2³ = 8 so this works
E: (3, 5)
2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work
F: (8, 5)
2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work
