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Nookie1986 [14]
3 years ago
9

The box plot on this page shows the total amount of time, in minutes, the students of a class surf the Internet every day:

Mathematics
2 answers:
maxonik [38]3 years ago
4 0

Answer:

It would be Part B

Step-by-step explanation:

taurus [48]3 years ago
3 0

Answer:

20

Step-by-step explanation:

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Help me please I need it
koban [17]
Unfortunately, you inadvertently cut off the instructions for this problem when you photographed it.  Could you try again, making certain to include the instructions?

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5 0
3 years ago
Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr
bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that \mu = 109, \sigma = 12

Sample of 25.

This means that n = 25, s = \frac{12}{\sqrt{25}} = 2.4

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{112 - 109}{2.4}

Z = 1.25

Z = 1.25 has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

7 0
3 years ago
Find all solutions to the equation.<br><br> 7 sin2x - 14 sin x + 2 = -5
cestrela7 [59]

\bf 7sin^2(x)-14sin(x)+2=-5\implies 7sin^2(x)-14sin(x)+7=0 \\\\\\ \stackrel{\textit{notice, this is just }ax^2+bx+c}{\stackrel{\stackrel{ax^2}{\downarrow }}{sin^2(x)}\stackrel{\stackrel{bx}{\downarrow }}{-2sin(x)}\stackrel{\stackrel{c}{\downarrow }}{+1}}=0\implies [sin(x)-1][sin(x)-1]=0 \\\\\\ sin(x)-1=0\implies sin(x)=1\implies \measuredangle x=sin^{-1}(1)\implies \measuredangle x=\cfrac{\pi }{2} \\\\\\ ~~~~~~~~~~~~~~\stackrel{\textit{and for all solutions using }n \in \mathbb{Z}}{\cfrac{\pi }{2}+2\pi n}

7 0
4 years ago
Read 2 more answers
The table below shows the average attendance of school events by the day of the week on which they are held. Average Attendance
natka813 [3]

Hello! :)

_____________ ☆ ☆_____________________

Answer:

407

Step-by-step explanation:

The answer is 407 because....

300/184 x 250

=407.60

So the answer is 407.60 which rounds to 407

ANSWER: X=407

______________ ☆ ☆______________________

Hope this helps! :)

By: BrainlyMember ^-^

Good luck!

5 0
3 years ago
Brainliest 70 Points! Write an equation representing the translation of f(x) = 7x + 3 down 4 units.
Schach [20]
F(x) = 7x - 1
Since it’s translated down 4 units, subtract 4 from the y intercept.
8 0
3 years ago
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