What is the completed table

Mathematics

1 answer:

nekit [7.7K]3 years ago

5 0

M║p
2 ║70
4 ║110
6 ║150
8 ║190

2x20=40+30=70

(2m)20+30=p

so you would multiply 2mx20 then whatever answer in this case it will be 40
so you would add 40+30=70 so p would equal 70
P=70

You might be interested in

A bike rental stand at the beach charges $5 to rent a bike then charges $2 every half hour it is rented is someone pay $70 for t

lord [1]

Answer:

Step-by-step explanation:

315

8 0

3 years ago

Layla is saving up money for a trip. She already has $650 saved and plans to save an additional $150 each month for the trip. Co

jonny [76]

The amount of money that Layla has saved, s, is going to be what the equation equals. She earns $150 each month, so that would be 150m (slope intercept form equation s=em+b). B is the y-intercept, or the amount that Layla already has saved, which is positive $650.

Your equation is:

s=150m+650

I hope this helps :)

8 0

3 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$