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sukhopar [10]
3 years ago
7

Help pzzzzzzzzzzzzzz

Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer: 1) The value of the 3 in option A is 10x the value of the 3 in option B

2) Option A has the 3 in the ones places, Option B has the 3 in the tenths place

Step-by-step explanation:

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Container A is cylinder with a radius of 6 units and a height of 6 units. A right cone has been carved from its base and has a h
padilas [110]

Answer:

V = π6²6 - (1/3)π6²6

Step-by-step explanation:

Volume of a cone is (1/3) that of a cylinder with the same radius and height.

Container A volume is the volume of a cylinder minus a cone.

V = πr²h - (1/3)πr²h

V = π6²6 - (1/3)π6²6

V = 144π units³

3 0
3 years ago
Satoko has 303030 tokens to spend at an arcade. The three lines represent the cost of playing Satoko's three favorite games for
nikdorinn [45]

Answer:

KOF

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Point M is located at (4,6) on a coordinate grid. Point M is translated 8 units to thr left and 9 units down to create point M'.
nata0808 [166]
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!

We have the point 4,6. 4 is the x, and 6 is the y.

Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.

Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.

So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!

The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²

Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.

So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.

So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²

Solving it out, we first need to work within the parenthesis. Can you solve it?

Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²

8²= 64
9²= 81

64+81 = 145.

So, the distance between point M and point M' would be 145 units

Hope this helps!

If it does not, please let me know so i can try to help!

4 0
3 years ago
Tamara is planting bushes around her house. So far today she has planted 5 bushes and she wants to plant at least 12 bushes toda
bixtya [17]

Answer:

b+5\geq 12

Step-by-step explanation:

Given:

Number of bushes planted = 5

Minimum number of bushes to be planted = 12

Let the number of bushes planted after planting 5 bushes be b.

Since, Tamara has already planted 5 bushes, total number of bushes planted is given as:

b+5

Now, as per question, total number of bushes should be 12 or greater than 12.

Therefore, b+5\geq 12.

6 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
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