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Zarrin [17]
3 years ago
14

Which expression is equivalent to StartFraction m minus 4 Over m + 4 EndFraction divided by (m + 2) ?

Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer:

a

Step-by-step explanation:

just took the quiz

antiseptic1488 [7]3 years ago
7 0

Answer: StartFraction m minus 4 Over (m + 4) (m + 2) EndFraction

Step-by-step explanation:

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If 4 classrooms can seat 188 students how many classrooms would be needed to seat 517 students?
Alenkinab [10]

Answer:

11 classrooms!!

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
… Please help I don’t understand
kondor19780726 [428]

9514 1404 393

Answer:

  18. x = {0, π/3, π, 5π/3, 2π}

  19. x = {0, 2π}

Step-by-step explanation:

You're supposed to use what you know about equation solving and trig functions to find the values of x that make these equations true. When the equation has a degree other than 1, you may need to use what you know about factoring and/or solving quadratic equations.

Inverse trig functions are helpful, but they don't always tell the whole story. You need to understand the behavior of each function over its whole period.

__

18. This equation is easily factored.

  -2sin(x)(1 -2cos(x)) = 0

The zero product rule tells you the product of these factors is zero only when one or more of the factors is zero. In other words, this resolves into the equations ...

  • sin(x) = 0
  • 1 -2cos(x) = 0

Your knowledge of the sine function tells you the solutions to the first of these equations is x = 0, π, 2π. (in the range 0 ≤ x ≤ 2π)

The second equation can be rewritten as ...

  1 = 2cos(x)

  1/2 = cos(x)

Your knowledge of the cosine function tells you this is true for ...

  x = π/3, 5π/3

So, all of the solutions to the given equation are ...

  x = {0, π/3, π, 5π/3, 2π}

__

19. Here, it is convenient to use a trig identity to make all of the variable terms be functions of the cosine.

  sin(x)² = 1 - cos(x)² . . . . the trig identity we need

  2 -(1 -cos(x)²) = 2cos(x) . . . . substitute for sin(x)²

  1 + cos(x)² = 2cos(x) . . . . . . . simplify

  cos(x)² -2cos(x) +1 = 0 . . . . . subtract 2cos(x), write as a quadratic in cos(x)

  (cos(x) -1)² = 0 . . . . . . . . . . . factor (recognize the perfect square trinomial)

  cos(x) = 1 . . . . . . . . . . . . . . take the square root, add 1

  x = 0, 2π . . . . . . . . values of x for which this is true

_____

The attachments show the solutions found using a graphing calculator. When solving these by graphing, it is generally most convenient to rewrite the equation to the form f(x) = 0. This can be done by subtracting the right-side expression, for example, as we did in the second attachment. That way, the solutions are the x-intercepts, which most graphing calculators can find easily.

3 0
3 years ago
A triangle with an area of 37 units? is dilated by a scale factor of . Find the area of
sergeinik [125]

Answer:

<u>58 units</u>

Step-by-step explanation:

I decided that one side is 37 units and another is 2 units, since that would make the area 37 units. (you can also use 74 units and 1 unit)

Then I multiplied 37 by 5/4, which equals a new length of 46.25 units, and I also multiplied 2 by 5/4, which equals a new length of 2.5 units.

Finally, I solve for the area of the triangle:

1/2(46.25 x 2.5) ≈ <u>58 units</u> (rounded to the nearest whole number)

7 0
3 years ago
Two automobiles leave the same city simultaneously and both head towards another city. The speed of one is 10 km/hour greater th
Veronika [31]

Answer:

5091 Km/hr and 505 km/hr

Step-by-step explanation:

Speed = Distance / Time

Let the speed of first automobile be 'x' and that of the second be 'y'

Since speed of one is 10 times greater than the other. therefore;

⇒ x = 10 y

also let time for faster automobile be 'T' and time for slower auto mobile be 't'

Since first arrive one hour earlier than second, therefore;

⇒ t = T + 1

⇒ For first automobile; x X T = 560 ; substituting for 'x' and 'T'. Therefore;

⇒ 10y (t+1) = 560

⇒ For Second automobile; y X t = 560

⇒ y = \frac{560}{t}

⇒ 10(\frac{560}{t})(t + 1) = 560

⇒ 5600 + \frac{5600}{t} = 560

⇒ 5600 - 560 =  -  \frac{5600}{t}

⇒ t = 1.11 hr

also ; T = 1.11 - 1 = 0.11 hr

Speed of 1st auto  = 560/0.11 = 5091 km /hr

Speed of 2nd auto = 560/1.11 = 505 km/hr

8 0
3 years ago
The Parker family drove a total of 180 miles on the road trip. This distance is 1.5 times the distance they drove on the first d
Veronika [31]

Parker family drove 120 miles on the first day

Step-by-step explanation:

Given:

Total miles driven on the road trip= 180 miles

solution:

Lets assume the distance drove on the first day is x

The total distance covered on the road trip is 180 miles.  so,

(x) *1.5 = 180

x=\frac{180}{1.5}

Hence, x = 120.

The distance travelled on the first day is 120 miles.

4 0
3 years ago
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