Answer:
![P(x = 5) = 0.2441](https://tex.z-dn.net/?f=P%28x%20%3D%205%29%20%3D%200.2441)
Step-by-step explanation:
Given
--- proportion that have very little confidence
--- sample
Required
Determine the probability that exactly 5 have very little confidence
This question will be solved using binomial probability:
![P(x) = ^nC_xp^x(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28x%29%20%3D%20%5EnC_xp%5Ex%281-p%29%5E%7Bn-x%7D)
In this case: x = 5.
So, we have:
![P(x = 5) = ^{10}C_5*0.48^5(1-0.48)^{10-5}](https://tex.z-dn.net/?f=P%28x%20%3D%205%29%20%3D%20%5E%7B10%7DC_5%2A0.48%5E5%281-0.48%29%5E%7B10-5%7D)
![P(x = 5) = ^{10}C_5*0.48^5*0.52^5](https://tex.z-dn.net/?f=P%28x%20%3D%205%29%20%3D%20%5E%7B10%7DC_5%2A0.48%5E5%2A0.52%5E5)
![P(x = 5) = 252*0.48^5*0.52^5](https://tex.z-dn.net/?f=P%28x%20%3D%205%29%20%3D%20252%2A0.48%5E5%2A0.52%5E5)
![P(x = 5) = 0.2441](https://tex.z-dn.net/?f=P%28x%20%3D%205%29%20%3D%200.2441)
Answer:
53
Step-by-step explanation:
Mean=Average
To find it, add al the numbers and divide by how many there are.
48+59+70+27+61=265
265/5=53
:)
The answer is 18+(-20) because if if you were going to solve that equation you would use the absolute value of -20 and then the opposite of the sign giving you 18-20. Hope this helps:)
Answer:
gallons of ice tea is left with Morris
Step-by-step explanation:
Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.
Morris has 2 3/4 gallons of ice tea
![2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}](https://tex.z-dn.net/?f=2%5Cfrac%7B3%7D%7B4%7D%3D%20%5Cfrac%7B2%2A4%2B3%7D%7B4%7D%3D%5Cfrac%7B11%7D%7B4%7D)
He gives 3/7 of it to her friend.
To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4
![\frac{11}{4}- \frac{3}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B4%7D-%20%5Cfrac%7B3%7D%7B7%7D)
Make the denominators same
![\frac{11*7}{4*7}- \frac{3*4}{7*4}](https://tex.z-dn.net/?f=%5Cfrac%7B11%2A7%7D%7B4%2A7%7D-%20%5Cfrac%7B3%2A4%7D%7B7%2A4%7D)
![\frac{77}{28}- \frac{12}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B77%7D%7B28%7D-%20%5Cfrac%7B12%7D%7B28%7D)
![\frac{65}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B65%7D%7B28%7D)
![\frac{65}{28} = 2 \frac{9}{28}](https://tex.z-dn.net/?f=%5Cfrac%7B65%7D%7B28%7D%20%3D%202%20%5Cfrac%7B9%7D%7B28%7D)