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olasank [31]
3 years ago
13

Doesn’t anyone know the answer to this

Mathematics
1 answer:
cricket20 [7]3 years ago
5 0
D. 8°
Explanation: A triangle is always 180° and we know of two points is 50° and 80°, the other must be 60, the 60° is cut in half so if it’s 30° the other side must be thirty. DBC Is 30+50
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Una compañía sabe que si produce "x" unidades mensuales su utilidad "u" se podría calcular con la expresión:
belka [17]

Answer:

Δf(u) /Δx  = 92,8    ( razón de cambio promedio)

Step-by-step explanation:

La expresión de la utilidad de la empresa u(x) en función de la cantidad de unidades producidas "x" es:

u(x) = 0,04*x² + 44*x  -4000

Entonces la razón de cambio promedio en un intervalo (a ; b)  en este caso ( 620 ;  600 ) viene dada por la expresión:

Δf(x)/ Δx  =  [ f(b)  -  f(a) ]/( b - a )

en donde  f(b)  y f(a) se obtienen por sustitución de los valores a y b es decir  600 y 620 respectivamente en la función f(x) = u(x) entonces

Δf(u) /Δx  =  [ u(b)  -  u(a) ]/( b -a )        (1)

u(b) =  0,04*(620)² + 44*(620) - 4000

u(b) = 15376 + 27280 -4000

u(b) = 2656 unidades

u(a)  = 0,04* (600)²  +  44* 600  - 4000

u(a)  = 14400  +  26400  - 4000

u(a) = 800

Sustituyendo esos valores en la ecuación 1

Δf(u) /Δx  =  2656 - 800 / 620 - 600

Δf(u) /Δx  = 92,8

5 0
4 years ago
For the transformation T, what is T-1? T : (x, y) (x + 4, y + 3) T-1: (x, y)
gavmur [86]
<span>The answer is:
T : (x, y) (x + 4, y + 3) 
</span>T⁻¹<span>: (x, y) (x - 4, y - 3)

</span><span>The basic principle is to find the inverse function of F,  such that T*</span>T⁻¹ = T⁻¹ * T = I.
8 0
3 years ago
Read 2 more answers
Factor the following polynomial completely. x4y+8x3y-6x2y2-48xy2 A. B. C. D.
Fynjy0 [20]

Answer:

What are the response choices? ;-;

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(1 point) Find the length traced out along the parametric curve x=cos(cos(4t))x=cos⁡(cos⁡(4t)), y=sin(cos(4t))y=sin⁡(cos⁡(4t)) a
Mazyrski [523]

The length of a curve C given parametrically by (x(t),y(t)) over some domain t\in[a,b] is

\displaystyle\int_C\mathrm ds=\int_a^b\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

In this case,

x(t)=\cos(\cos4t)\implies\dfrac{\mathrm dx}{\mathrm dt}=-\sin(\cos4t)(-\sin4t)(4)=4\sin4t\sin(\cos4t)

y(t)=\sin(\cos4t)\implies\dfrac{\mathrm dy}{\mathrm dt}=\cos(\cos4t)(-\sin4t)(4)=-4\sin4t\cos(\cos4t)

So we have

\displaystyle\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2=16\sin^24t\sin^2(\cos4t)+16\sin^24t\cos^2(\cos4t)=16\sin^24t

and the arc length is

\displaystyle\int_0^1\sqrt{16\sin^24t}\,\mathrm dt=4\int_0^1|\sin4t|\,\mathrm dt

We have

\sin(4t)=0\implies4t=n\pi\implies t=\dfrac{n\pi}4

where n is any integer; this tells us \sin(4t)\ge0 on the interval \left[0,\frac\pi4\right] and \sin(4t) on \left[\frac\pi4,1\right]. So the arc length is

=\displaystyle4\left(\int_0^{\pi/4}\sin4t\,\mathrm dt-\int_{\pi/4}^1\sin4t\,\mathrm dt\right)

=-\cos(4t)\bigg_0^{\pi/4}-\left(-\cos(4t)\bigg_{\pi/4}^1\right)

=(\cos0-\cos\pi)+(\cos4-\cos\pi)=\boxed{3+\cos4}

7 0
3 years ago
What is 2 ½ divided by ⅘
Svet_ta [14]

Answer:

Step-by-step explanation:

2.5(2 1/2) / 0.8(4/5)

<h3>= <u>3.125</u></h3>

<em>Hope this helped!!</em>

8 0
3 years ago
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