First, determine the z-score of 675.
z = (675 - 500) / 100 = 1.75
The z-score of 500 is,
z = 0.
Subtracting the z-scores will give us 1.75. This is equal to 0.9599.
= 0.9599 - 0.5 = 0.4599
Multiplying this to the given number of light bulbs,
n = 0.4599 x 5000 = 2299.5
Therefore, there is approximately 2300 light bulbs expected to last between 500 to 675 hours.
Answer:
3
Step-by-step explanation:
3+3_3=3
after that 3+2+6+7+7+8+8+9+9+9+9+9+0+0+8+6+5+4+ 5=?
u will do the answer and it will be done
Answer:
P = 0.006
Step-by-step explanation:
Given
n = 25 Lamps
each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours
Find probability that the lamp will be burning at end of 1300 hours period.
As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have
Suppose i represents lamps
P (∑i from 1 to 25 (
> 1300)) = 1300
= P(
>
) where
represents mean time of a single lamp
= P (Z>
) Z is the standard normal distribution which can be found by using the formula
Z = Mean Time (
) - Life time of each Lamp (50 hours)/ (SD/
)
Z = (52-50)/(4/
) = 2.5
Now, P(Z>2.5) = 0.006 using the standard normal distribution table
Probability that a lamp will be burning at the end of 1300 hours period is 0.006
Answer:

Step-by-step explanation:
<u>Step 1: Set the second equation into the first
</u>




<u>Step 2: Solve the second equation
</u>


Answer: 