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sergeinik [125]
2 years ago
11

Write the following expression using an exponent: 5⋅5⋅5⋅5

Mathematics
2 answers:
Vesna [10]2 years ago
8 0

Answer:

5^4

Step-by-step explanation:

i hope this helps :)

777dan777 [17]2 years ago
3 0

Answer:

5^4

Step-by-step explanation:

exponents are the number being multiplied by itself and you can see 4 fives so it would be 5^4

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kolbaska11 [484]

Answer:

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c= a+2b+c

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3 years ago
Chloe drew a triangle with side lengths of 30 centimeters, 24 centimeters, and 18 centimeters. Juan drew a triangle with side le
vlada-n [284]

Answer:

A and B

Step-by-step explanation:

Each side in Chloe's triangle is 1.5 times the length of each side in Juan's triangle.  Thus, they are 'similar' by the <u>math </u>definition of that word, by the SSS Rule for Similar Triangles.

That means they are different only in size. So, their angle measures are the same and they are the same shape.

A and B are true.

C is never true, because the sum of all 3 angles in a triangle is always 180°.

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5 0
3 years ago
18.25=4(1.5-3.75x)-.25(4x-5) wat is x?
sdas [7]
The answer is x= - 11/ 16
You can check this by plugging in x for -11/16



5 0
3 years ago
Please help!!! I will give you BRIANLEIST AND A HEARTED COMMENT AND 5 STARS if you can explain this:(
Agata [3.3K]

Answer:

I can do this give me a min

4 0
3 years ago
Question :
Elza [17]

Answer:

C) 405.3 ft

Step-by-step explanation:

A triangle is a polygon with three angles and three sides. Types of triangle are scalene, isosceles, equilateral, right angled triangle.

Given a triangle with angles A, B, C and the corresponding sides directly opposite to the angles as a, b, c. The sine rule states that:

\frac{a}{sin(A)}= \frac{b}{sin(B)} =\frac{c}{sin(C)}

In the triangle formed by point C, ship B and ship A, we have ∠A = 82°, ∠B = 78°, c = AB = 140 ft. Hence:

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∠C = 20°

Using sine rule:

\frac{c}{sin(C)}=\frac{a}{sin(A)}\\\\\frac{140}{sin(20)}=\frac{a}{sin(82)}\\\\a=    \frac{140*sin (82)}{sin(20)}\\\\a=405.3\ ft

a =  distance from Ship B to the signal fire at point C

8 0
3 years ago
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