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V125BC [204]
3 years ago
14

Translate the verbal expression to an algebraic expression: Twice the sum of a number and 4. Gimme an answer quick. In a SENTENC

E
Mathematics
2 answers:
tester [92]3 years ago
5 0

Answer:

2(x+4)

Step-by-step explanation:

Brainliest are appreciated :)

defon3 years ago
4 0

Answer:

if x=3 what is the value of this expression

Step-by-step explanation:

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How many times farther is Mars than Venus from the sun?
Alexandra [31]

Answer:

75,000,000

Step-by-step explanation:

To find how much father Mars is to Venus to the sun you just subtract the two numbers.

7 0
3 years ago
Read 2 more answers
2+2=?<br> and it's not 4. :)
Sindrei [870]

Answer:

a carrot? yea a carrot. :D

8 0
3 years ago
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A chocolate bar is packaged in a box on the shape of a triangular prism.
BartSMP [9]

Answer:

20 cm

Step-by-step explanation:

A prism's volume is found using the formula A = B*h where B is the are of the base. Here the volume v = 250 and the B = 12.5. Substitute the values and solve for h.

250 = 12.5*h

250/12.5 = h

20 = h

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=11%2B5x%3D2x-4" id="TexFormula1" title="11+5x=2x-4" alt="11+5x=2x-4" align="absmiddle" class="
stira [4]
11+4 = 2x-5x
15=-3x
X=-5
4 0
3 years ago
Read 2 more answers
For the following exercises, determine whether the relation is a function.
Nutka1998 [239]

Answer:

The given relation {(5,2),(6,1),(6,2),(4,8)} is not a function.

Step-by-step explanation:

The relation {(5,2),(6,1),(6,2),(4,8)} is given.

It is required to determine whether the given relation is a function.

To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.

Step 1 of 1

The given relation is {(5,2),(6,1),(6,2),(4,8)}.

The set of the first components of each ordered pair is called the domain.

From the relation, the domain is {5,6,6,4}.

The set of the second components of each ordered pair is called the range.

From the relation, the range is {2,1,2,8}.

The domain of the function does not have a unique range. So, the given relation is not a function.

3 0
2 years ago
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