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serg [7]
3 years ago
8

The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to

the shoreline. Write an equation that represents this path.

Mathematics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:

Step-by-step explanation:

To define the perpendicular line we need to first know the slope of the reference line graphed.

m=(y2-y1)/(x2-x1) we have points (0,5) and (2,1)

m=(1-5)/(2-0)

m=-4/2

m=-2

For lines to be perpendicular their slopes must satisfy

m1m2=-1, we have a line with a slope of -2 so

-2m=-1

m=1/2, so our perpendicular line is so far

y=x/2+b, it must have point (3,2) so we can solve for b

2=3/2+b

b=1/2, so the swimmer will travel along the line

y=x/2+1/2

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Gemiola [76]

a) The solution for the equation 2x + 16 = 5x + 4  is x=4.

b) The solution for the equation 3x − 5 = 2x + 14 is x=19.

c) The solution for the equation 5x − 5 = x + 15 is x=5.

<u>Step-by-step explanation:</u>

<u>a) The given equation is  2x + 16 = 5x + 4 </u>

  • From the above equation, it can be found that the equation consists of x terms and constant terms.
  • Therefore, bring all the x terms on one side and the constant terms on other side of the equation.
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⇒ 16-4 = 5x-2x

⇒ 12 = 3x

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The solution for the given equation is x=4.

<u>To check, substitute x=4 in the equation :</u>

2(4) + 16 = 5(4) + 4

8+16 = 20+4

24 = 24

Therefore, the solution x=4 satisfies the equation 2x + 16 = 5x + 4

Similarly,

<u>b) The given equation is 3x − 5 = 2x + 14</u>

⇒ 3x-2x = 14+5

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The solution for the given equation is x=19.

<u>To check, substitute x=19 in the equation :</u>

3(19) - 5 = 2(19) + 14

57-16 = 38+14

52 = 52

Therefore, the solution x=19 satisfies the equation 3x − 5 = 2x + 14

Similarly,

<u>c) The given equation is 5x − 5 = x + 15</u>

⇒ 5x-x = 15+5

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⇒ x = 20/4

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The solution for the given equation is x=5.

<u>To check, substitute x=5 in the equation :</u>

5(5) - 5 = 5 + 15

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3 years ago
A school has 17 tables in the cafeteria. Each table seats 12 students. What is the
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12 students can fit at 1 table and there are 17 tables.

So we have (12)(17) which is 204.

So the greatest number of students that can be seated din the cafeteria is 204 students.

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