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Alekssandra [29.7K]
3 years ago
8

Hello! I need help on this Hw Question The question is Which of the Solutions (A,B,C and D can be a solution to the graph?

Mathematics
1 answer:
blagie [28]3 years ago
8 0
I believe the answer to your question is A
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Whiskers the cat weighs 2 and 2 over 3 kg.piglio weighs 4 kg. How many times as heavy as piglio is whiskers
ruslelena [56]

Answer:

Whiskers is two-third times as heavy as piglio is.

Step-by-step explanation:

Given:

Weight of whiskers is, W=2\frac{2}{3}\ kg

Weight of piglio is, P=4\ kg

In order to compare their weights, we have to divide both the weights and then express one weight in terms of the other.

Therefore, dividing whiskers weight by piglio's weight, we get:

\frac{W}{P}=2\frac{2}{3}\div 4\\\frac{W}{P}=\frac{8}{3}\div \frac{4}{1}(\textrm{4 can be rewritten as 4/1 in fraction form})

Now, when we divide two fractions, we replace the division sign by multiplication and reverse the second fraction. This gives,

\frac{W}{P}=\frac{8}{3}\times \frac{1}{4}\\\frac{W}{P}=\frac{8\times 1}{3\times 4}\\\frac{W}{P}=\frac{2}{3}

Now, expressing 'W' in terms of 'P', we multiply both sides by 'P. This gives,

W=\frac{2}{3}P

Therefore, the weight of whiskers is two-third times as heavy as piglio is.

4 0
4 years ago
9 is 1/10 of 90 yes or no
o-na [289]

9  is  1/10  of  90  yes.

7 0
4 years ago
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Can I get some help please? I WILL MARK BRAINLIEST AND 50 POINTS! DUE TOMORROW BECAUSE GRADES ARE COMING OUT TOMORROW AND THIS I
vichka [17]

Wait this is tricky let me go ask my sis she is coming the answer is in the comeent!

4 0
3 years ago
Find the residual values, and use the graphing calculator tool to make a residual plot. A 4-column table with 5 rows. The first
Georgia [21]

Answer:

Solution-

We know that,

Residual value = Given value - Predicted value

The table for residual values is shown below,

Plotting a graph, by taking the residual values on ordinate and values of given x on abscissa, a random pattern is obtained where the points are evenly distributed about x-axis.

We know that,

If the points in a residual plot are randomly dispersed around the horizontal or x-axis, a linear regression model is appropriate for the data. Otherwise, a non-linear model is more appropriate.

As, in this case the points are distributed randomly around x-axis, so the residual plot show that the line of regression is best fit for the data set.

Hope this helps!

Step-by-step explanation:

4 1
4 years ago
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A line segment ad, contains points b & c such that c is between a and d, and b is between a and
egoroff_w [7]

If you drew out this line segment with the points in the order we are given them, the segment would be labeled as a, b, c, d in that order. We are given a measure for ab, and we are also given a measure for bd with c being ignored for a minute. The entire length of the segment can be found by adding ab and bd. 6 + 23 = ad and ad = 29. So the length of the whole segment is 29. We have the length of cd given to be equal to ab, so cd = 6. ab + bc + cd = ad and we are looking for bc. Since we have the other lengths and the length of the whole segment, we fill in accordingly: 6 + bc + 6 = 29. Solving for bc we get bc = 17.

3 0
3 years ago
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