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lana66690 [7]
3 years ago
6

Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select

ed. Find the probability of selecting a seven and then selecting a nine.
The probability of selecting a seven and then selecting a nine is
(Round to three decimal places as needed.)
Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer: 0.006

Step-by-step explanation:

The probability is:

(4/52) × (4/51)

= 4/663

≈ 0.006

Elina [12.6K]3 years ago
3 0

Answer:

0.006

Step-by-step explanation:

On the first draw, there are 52 cards, 4 of which are sevens.

On the second draw, there are 51 cards, 4 of which are nines.

The probability is:

(4/52) × (4/51)

= 4/663

≈ 0.006

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Since P(<em>X</em> = <em>x</em>) = 0.3 for all 0 ≤ <em>x</em> ≤ <em>α</em>, we have

\displaystyle\int_{-\infty}^\infty P(X=x)\,\mathrm dx=1\implies0.3\int_0^\alpha\mathrm dx=0.3\alpha=1\implies\alpha=\dfrac{10}3

So,

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